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son4ous [18]
3 years ago
13

At burns high school 3/5 of the students are females of the female students 1/3 of them play volleyball what fraction of the stu

dents in burn high school are girls that play volleyball
Mathematics
1 answer:
Ratling [72]3 years ago
3 0

For this case, we want to know what fraction of the Burns High School girls play volleyball. For this, we make a rule of three based on the female students

\frac {3} {5} ---------> 1\\\frac {1} {3} ---------> x

Where "x" represents the fraction of women who play volleyball

x = \frac {\frac {1} {3} * 1} {\frac {3} {5}}\\x = \frac {5} {9}

Thus,\frac {5} {9}are women who play volleyball.

Answer:

\frac {5} {9}


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Suppose that y varies directly with x<br> and y = 10 when x = 20. What is y<br> when x = 15?
tresset_1 [31]

Answer: y = 7.5

Step-by-step explanation:

Suppose that y varies directly with x

That is, y∝x

Convert y∝x to a full equation by introducing a constant k to the right hand side.

Therefore, y = kx

Given that y = 10 and x = 20

Substitute y and x in the equation above. We have;

10 = k(20)

10 = 20k

20k = 10

k = 10/20

k = 0.5

Since k = 0.5, the equation y = kx becomes y = 0.5x

Now, to find y if x = 15, substitute x in equation y = 0.5x

Therefore, y = 0.5(15)

y = 7.5

5 0
3 years ago
Find the fifth term in the arithmetic sequence that begins at 1.5 and has a common difference of 6.6.
astraxan [27]
I think it's 34.5 (I need more letters so I'm typing this)
4 0
3 years ago
Manuel needs to make a total of 60 deliveries this week. So far he has completed 36 of them. What percentage of his total delive
Alenkasestr [34]

Answer:

60%

Step-by-step explanation:

It’s simple

He needs to do 60, he has done 36

Percentage = (36/60) * 100

= 60%

5 0
3 years ago
How do u solve P=IRT solve for t
Roman55 [17]
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3 0
3 years ago
AYUDA CON ESTO!!! ALGUIEN PORFAVOR
Gre4nikov [31]

Answer:

Problem 1)  frequency:  160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

\frac{200}{60} = \frac{10}{3} \approx  3.33   loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

\frac{200}{65} = \frac{40}{13} \approx  3.08   loops per minute

then the period is:

\frac{13}{40} =0.325\,\,\,minutes

Therefore runner B has the smaller period

8 0
3 years ago
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