Let P-6. 4) be a point on rectangle PQRS, What are the coordinates

Mathematics

1 answer:

Stels [109]3 years ago

5 0

Answer:

The coordinates of P' are $(-\frac{9}{4},\frac{3}{2})$

Step-by-step explanation:

Given a point (x,y). If we have a dilation by a scale factor of r, centered at the origin, we have that the coordinates of (x,y) in the new system is given by (r*x,r*y).

Assumign that this dilation is centered at the origin, then if P is the point (-6,4) then the point P' is $(-6\cdot \frac{3}{8},4\cdot \frac{3}{8}) = (-\frac{9}{4},\frac{3}{2})$

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