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mr Goodwill [35]
3 years ago
11

Maria has gotten scores of 75, 77, 81 and 84 (out of a possible 100) on the four midterm examinations for a math class. If each

of these midterms counts as 15% of the total grade in the class and the final exam counts as 40% of the total grade, what must she get as a score (out of 100 possible) on the final examination to get at least 85% as her total grade in the class?
Mathematics
1 answer:
timofeeve [1]3 years ago
3 0

Answer:

93.63

Therefore, she need to get a minimum of 93.63 out of 100 in the final exam

Step-by-step explanation:

Given;

Each midterm exam = 15% of total grade

Final exam = 40% of total grade

Midterm scores = 75, 77, 81 and 84 (out of a possible 100)

Total midterm score = 75+77+81+84 = 317

To determine the grade of the four midterm exams in the total score;

We need to find the 15% of the midterm score;

= 15% of 317

= 0.15×317

= 47.55 %

To get a minimum score of 85 % of the total score, the amount of the total score to be secured in the final exam is;

Final exam = 85% - 47.55% = 37.45%

Since final exam is 40% of the total score;

It means she need to get 37.45% out of 40% of the final exam.

Converting it to a score of 100;

Final exam score = 37.45/40 × 100

Final exam score = 93.63

Therefore, she need to get a minimum of 93.63 out of 100 in the final exam

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<h2>○=> <u>Correct options</u> :</h2><h2>□\color{plum}\tt\bold{(C) \: SR = 27}</h2><h2>□\color{plum}\tt\bold{(D) \: QR = 54 }</h2><h3><u>Steps to derive the correct options</u> :</h3>

Since two sides and one included angle is equal in △PQS and △PRS, we can conclude that they are congruent under the SAS congruence criterion.

Which means :

▪︎Angle S = Angle S

▪︎PS = PS

▪︎QS = RS

Given :

Measure of segment QS = 6n+3

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Thus :

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= \tt2n = 8

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\hookrightarrow\color{plum}\tt n = 4

Thus, the value of n = 4

Measure of segment QS :

=\tt 6n + 3

= \tt6 \times 4 + 3

= \tt24 + 3

\color{plum}\tt \: \bold{QS = 6n + 3 = \tt\bold{27}}

Thus, measure of QS = 27

Measure of RS :

=\tt 4n + 11

=\tt 4 × 4 + 11

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\color{plum}\tt \: \bold{RS = 4n + 11 = \tt\bold{27}}

Measure of QR :

=\tt 27+27

\color{plum}\tt \: \bold{QR = 27+27 \tt\bold{=54}}

Thus :

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▪︎RS = 27

▪︎QR = 54

Therefore, the correct options are :

▪︎(C) SR = 27

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Step-by-step explanation:

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