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rewona [7]
3 years ago
8

Jack is framing the roof of a structure using a triangle and two exterior angles.

Mathematics
2 answers:
Ne4ueva [31]3 years ago
4 0

The answer is  A and B

sergeinik [125]3 years ago
4 0

Answer:

a b

Step-by-step explanation:

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HRLP ME PLEASE BRO PLEASE ALL I NEED IS THE ANSWER
earnstyle [38]
Answer:
It’s the first one
6 0
2 years ago
Am trying to find the value of r<br> 1/r + 2/1-r = 4/r^2
Mashcka [7]
<span>1/r + 2/1-r = 4/r^2

1-r+2r/r(1-r)=4/r^2
(1+r)/r(1-r)=4/r^2   cancle r both side

1+r/1-r=4/r

cross multiply 
r+r^2=4-4r
r^2+4r+r-4=0
r^2+5r-4=0
r^2+4r+r-4=0
solve it for r factor it...



</span>
6 0
2 years ago
Find m∠U.<br> Write your answer as an integer or as a decimal rounded to the nearest tenth.
galina1969 [7]

Answer:

Answer:

50.2

Step-by-step explanation:

ut =  \sqrt{ {6}^{2}  +  {5}^{2} }   \\  \sqrt{36 + 25}  \\  \sqrt{61 }  \\ using \: cosine \: rule \\ cos \: u =  \frac{ {5}^{2} + 61 - 36 }{2 \times 5 \times  \sqrt{61} }  \\  \\  =  \frac{25 + 61 - 36}{78}  \\  \\  = \frac{50}{78 }  \\  \cos \: u = 0.64 \\ m \:u = 50.2

6 0
2 years ago
A shopping mall charges $30 per vehicle plus $2 per person as an admission fee. The total charge for a vehicle with x people is
Alecsey [184]
Changing the 30 to 10 is a 20 unit drop ( 30-10=20)
 so the line would shift vertically down by 20

<span>The line will shift vertically down by $20.</span>
7 0
2 years ago
Which equation represents a graph with a vertex at (–3, 2)?
lesya [120]

<u>We will proceed to find the equations in the vertex form in each case</u>

<u>Part a)</u> y= 4x^{2}+24x+38

Group terms that contain the same variable, and move the constant to the opposite side of the equation

y-38= 4x^{2}+24x

Factor the leading coefficient

y-38= 4(x^{2}+6x)

Complete the square. Remember to balance the equation by adding the same constants to each side

y-38+36= 4(x^{2}+6x+9)

y-2= 4(x+3)^{2}

y= 4(x+3)^{2}+2

<u>the vertex is the point (-3,2)</u>

<u>Part b)</u>  y=4x^{2}-24x+38

Group terms that contain the same variable, and move the constant to the opposite side of the equation

y-38= 4x^{2}-24x

Factor the leading coefficient

y-38= 4(x^{2}-6x)

Complete the square. Remember to balance the equation by adding the same constants to each side

y-38+36= 4(x^{2}-6x+9)

y-2= 4(x-3)^{2}

y= 4(x-3)^{2}+2

<u>the vertex is the point (3,2)</u>

<u>Part c) </u> y=4x^{2}+12x+2

Group terms that contain the same variable, and move the constant to the opposite side of the equation

y-2= 4x^{2}+12x

Factor the leading coefficient

y-2= 4(x^{2}+3x)

Complete the square. Remember to balance the equation by adding the same constants to each side

y-2+9= 4(x^{2}+3x+2.25)

y+7= 4(x+1.5)^{2}

y= 4(x+1.5)^{2}-7

<u>the vertex is the point (-1.5,7)</u>

<u>Part d)</u> y=4x^{2}+16x+13

Group terms that contain the same variable, and move the constant to the opposite side of the equation

y-13= 4x^{2}+16x

Factor the leading coefficient

y-13= 4(x^{2}+4x)

Complete the square. Remember to balance the equation by adding the same constants to each side

y-13+16= 4(x^{2}+4x+4)

y+3= 4(x+2)^{2}

y= 4(x+2)^{2}-3

<u>the vertex is the point (-2,-3)</u>

therefore

<u>the answer is </u>

y= 4x^{2}+24x+38

3 0
3 years ago
Read 2 more answers
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