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3 years ago

8

Jack is framing the roof of a structure using a triangle and two exterior angles.

2 answers:

Ne4ueva [31]3 years ago

4 0

The answer is A and B

sergeinik [125]3 years ago

4 0

Answer:

a b

Step-by-step explanation:

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HRLP ME PLEASE BRO PLEASE ALL I NEED IS THE ANSWER

earnstyle [38]

Answer:
It’s the first one

6 0

2 years ago

Am trying to find the value of r<br> 1/r + 2/1-r = 4/r^2

Mashcka [7]

<span>1/r + 2/1-r = 4/r^2

1-r+2r/r(1-r)=4/r^2
(1+r)/r(1-r)=4/r^2 cancle r both side

1+r/1-r=4/r

cross multiply
r+r^2=4-4r
r^2+4r+r-4=0
r^2+5r-4=0
r^2+4r+r-4=0
solve it for r factor it...

</span>

6 0

2 years ago

Find m∠U.<br> Write your answer as an integer or as a decimal rounded to the nearest tenth.

galina1969 [7]

Answer:

Answer:

50.2

Step-by-step explanation:

$ut = \sqrt{ {6}^{2} + {5}^{2} } \\ \sqrt{36 + 25} \\ \sqrt{61 } \\ using \: cosine \: rule \\ cos \: u = \frac{ {5}^{2} + 61 - 36 }{2 \times 5 \times \sqrt{61} } \\ \\ = \frac{25 + 61 - 36}{78} \\ \\ = \frac{50}{78 } \\ \cos \: u = 0.64 \\ m \:u = 50.2$

6 0

2 years ago

A shopping mall charges $30 per vehicle plus $2 per person as an admission fee. The total charge for a vehicle with x people is

Alecsey [184]

Changing the 30 to 10 is a 20 unit drop ( 30-10=20)
so the line would shift vertically down by 20

<span>The line will shift vertically down by $20.</span>

7 0

2 years ago

Which equation represents a graph with a vertex at (–3, 2)?

lesya [120]

<u>We will proceed to find the equations in the vertex form in each case</u>

<u>Part a)</u> $y= 4x^{2}+24x+38$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-38= 4x^{2}+24x$

Factor the leading coefficient

$y-38= 4(x^{2}+6x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-38+36= 4(x^{2}+6x+9)$

$y-2= 4(x+3)^{2}$

$y= 4(x+3)^{2}+2$

<u>the vertex is the point $(-3,2)$ </u>

<u>Part b)</u> $y=4x^{2}-24x+38$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-38= 4x^{2}-24x$

Factor the leading coefficient

$y-38= 4(x^{2}-6x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-38+36= 4(x^{2}-6x+9)$

$y-2= 4(x-3)^{2}$

$y= 4(x-3)^{2}+2$

<u>the vertex is the point $(3,2)$ </u>

<u>Part c) </u> $y=4x^{2}+12x+2$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-2= 4x^{2}+12x$

Factor the leading coefficient

$y-2= 4(x^{2}+3x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-2+9= 4(x^{2}+3x+2.25)$

$y+7= 4(x+1.5)^{2}$

$y= 4(x+1.5)^{2}-7$

<u>the vertex is the point $(-1.5,7)$ </u>

<u>Part d)</u> $y=4x^{2}+16x+13$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-13= 4x^{2}+16x$

Factor the leading coefficient

$y-13= 4(x^{2}+4x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-13+16= 4(x^{2}+4x+4)$

$y+3= 4(x+2)^{2}$

$y= 4(x+2)^{2}-3$

<u>the vertex is the point $(-2,-3)$ </u>

therefore

<u>the answer is </u>

$y= 4x^{2}+24x+38$

3 0

3 years ago

Read 2 more answers