Answer:
The correct option is B. The area of the figure is 40.4 units².
Step-by-step explanation:
The line AB divides the figure in two parts one is a rectangle and another is semicircle.
The distance formula is

The length of AB is

The length of AD is

Since AB=AD, therefore ABCD is a square. The area of the of square is

The area of square is 29 units².
The area of a semicircle is

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

The area of the semicircle is

The area of the figure is

Therefore the area of the figure is 40.4 units². Option B is correct.
First you graph it using a graphing calculator, you look at the table of values to find out one point in which y= 0. The first one that comes up is when x=1.
If you don't have a graphing calculator you can use trial and error by inputing some numbers into x until you get y= 0.
Once you have an x value which makes y=0, you can start factorizing it.
you divide 6x3 +4x2 -6x - 4 into (x-1) which is when y =0
to get 6x2+10x+4
This can be used to write the polynomial as (x-1)(6x2 +10x+4)
you then factorize the second bracket, 6x2 +10x+4.
you can take the 2 outside to give you 2(3x2 +5x+2)
you can factorize this to become 2(3x+2)(x+1)
Now you just substitute your factorized second bracket into your unfactorized second bracket to give you 2(3x+2)(x+1)(x-1).
From this you can deduce that k= 1
Answer:
your answer should be x = -3