3 years ago

What is the sum of the first 14 terms of the sequence : an=6n-12

1 answer:

5 0

A1=6*1-12=-6 arithmetic sequence
a14=6*14-12=72
sum =n(a(1)+a(n))/2
sum =14*(-6+72)/2=462

You might be interested in

TiliK225 [7]

Answer:

I am a girl and I refuse to do such a horrendous propostoruos futile thing

8 0

2 years ago

adelina 88 [10]

F.. took this test last week

7 0

3 years ago

vovikov84 [41]

Answer:

0.104 (10.4%)

Step-by-step explanation:

$UCL = \bar{p}+z(\sigma)$

$\sigma = p(1-)) Vn = 1.02(1-202)) 5$ = 0.028

$\thereforeUCL = .02+(3x0.028)$ = 0.104

$\thereforeUCL$ = 10.4%

4 0

3 years ago

mihalych1998 [28]

Answer:

0.56

Step-by-step explanation:

Percent means 'per 100'. So 56% means 56 per 100 or simply 56/100. If you divide 56 by 100, you'll get 0.56.

56/100 = 0.56

5 0

2 years ago

Elanso [62]

Answer:

A for first one and C

Step-by-step explanation:

4 0

2 years ago