
It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if
</span><span>

</span><span>In notation we write respectively
</span>

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence

Thus these two limits, the one from above and below are equal if and only if
4c + 20 = 16 - c²<span>
Or in other words, the limit as x --> 4 of f(x) exists if and only if
4c + 20 = 16 - c</span>²

That is to say, if c = -2, f(x) is continuous at x = 4.
Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers 
The answer is between B and C but... I'm kinda leaning more towards B but, you choose which one you think is right.
Hope I helped you. :)
Answer:
D. 1200 mg
Step-by-step explanation:
In order to find the solution we need to understand that a dosage of 20 mg/kg means that 20 mg are administered to the patient for each kg of his/her weight.
So, if the patient weight is 60 kg then:
Total drug X = (20mg/Kg)*(60Kg)=1200mg.
In conclusion, 1200 mg will be administered to the patient, so the answer is D.
To complete the square, you would add to both sides (8/2)^2 = (4)^2 = 16. So, the correct answer would be D.
Answer: 15
Step-by-step explanation:
Which represents Nikiya’s cost per hour