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3 years ago

What is the slope of the line that goes through the points (1,-5) and (4,1)?

Mathematics

2 answers:

Anna007 [38]3 years ago

3 0

Answer:

D. 2

Step-by-step explanation:

(1 - -5)/(4 - 1) = 6/3 = 2

guapka [62]3 years ago

3 0

Answer: 2

Step-by-step explanation:

The slope of a line through two points (x₁, y₁) and (x₂, y₂) is given by (y₂ - y₁)/(x₂ - x₁). In this case, x₁ = 1, y₁ = -5, x₂ = 4, and y₂ = 1. So the slope is:

(1 - (-5))/(4 - 1) = 6/3 = 2

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In ΔJKL, k = 9.6 cm, l = 2.7 cm and ∠J=43°. Find ∠L, to the nearest 10th of a degree.

Bogdan [553]

Answer:

L = 10.64°

Step-by-step explanation:

From the given information:

In triangle JKL;

line k = 9.6 cm

line l = 2.7 cm; &

angle J = 43°

we are to find angle L = ???

We can use the sine rule to determine angle L:

i.e

$\dfrac{j}{SIn \ J} = \dfrac{l}{ SIn \ L}$

Using Pythagoras rule to find j

i,e

j² = k² + l²

j² = 9.6²+ 2.7²

j² = 92.16 + 7.29

j² = 99.45

$j = \sqrt{99.45}$

j = 9.97

∴

$\dfrac{9.97}{Sin \ 43} = \dfrac{2.7}{ Sin \ L}$

${9.97 \times Sin (L ) = (2.7 \times Sin \ 43)$

$= Sin \ L = \dfrac{ (2.7 \times Sin \ 43)}{9.97 } \\ \\ = Sin \ L = \dfrac{ (2.7 \times 0.6819)}{9.97 } \\ \\ = Sin \ L = 0.18466 \\ \\ L = Sin^{-1} (0.18466) \\ \\ L = 10.64 ^0$

3 0

3 years ago

Find the interior angle of a regular polygon which has 6 sides

AveGali [126]

Answer:

120°.

Step-by-step explanation:

The sum of all interior angles in a polygon with $n$ sides ( $n\in \mathbb{Z}$ , $n \ge 3$ ) is equal to $(n - 2) \cdot 180^{\circ}$ . (Credit: Mathsisfun.)