Answer:
a. V = (20-x)
b . 1185.185
Step-by-step explanation:
Given that:
- The height: 20 - x (in )
- Let x be the length of a side of the base of the box (x>0)
a. Write a polynomial function in factored form modeling the volume V of the box.
As we know that, this is a rectangular box has a square base so the Volume of it is:
V = h *
<=> V = (20-x)
b. What is the maximum possible volume of the box?
To maximum the volume of it, we need to use first derivative of the volume.
<=> dV / Dx = -3
+ 40x
Let dV / Dx = 0, we have:
-3
+ 40x = 0
<=> x = 40/3
=>the height h = 20/3
So the maximum possible volume of the box is:
V = 20/3 * 40/3 *40/3
= 1185.185
Answer:
9 inches
Step-by-step explanation:
The radius is 1/2 of the diameter
r = d/2
r = 18/2 = 9
Answer:
684
Step-by-step explanation:
57 times 12
12 weeks times 57 pages= 684 pages in 12 weeks
Since it's a wall, I'm guessing it will only have access to half the circle? Therefore:
<em>Circle area formula: </em>πr²
<em>Radius:</em> 12/2 = 6ft
<em>Our case:</em>
(π * 6²)/2 =
36π/2 =
18π = 56.55ft²
If you can graph in slope intercept, your new equations would be: y= -2x-1 and y= 2/3x-3.
Just graph those now since it should be easier.