How many groups of 1 2/3 are in 4 1/3
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The increasing order of the complex numbers is (√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ = (-1 + √3i)¹² < (√3 - √3i)⁴.
<h3>Absolute values of the complex numbers</h3>The absolute values of the complex numbers are determined as follows;
(sqrt3-sqrt3i)^4 = (√3 - √3i)⁴
(-1+sqrt3i)^12 = (-1 + √3i)¹²
(sqrt 3-i)^6 = (√3 - i)⁶
(sqrt2-sqrt2i)^8 = (√2 - √2i)⁸
(sqrt2-i)^6 = (√2 - i)⁶
Increasing order of the complex numbers;
(√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ = (-1 + √3i)¹² < (√3 - √3i)⁴.
Learn more about complex numbers here: brainly.com/question/10662770
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