Answer:
A. (2,5)
because 3×2 is 6, 6-1 is 5
so y=5
Answer:
The answer is 0.8788
Step-by-step explanation:
<em>From question given, let us recall the following:</em>
<em>We know that Ƶα /2 * √p (1-p)/n</em>
<em>when we use n≤ 5000/10 =500</em>
<em> P = 0.75</em>
<em>The Margin of error = 0.03</em>
<em>Putting this values together we arrive at </em>
<em> Ƶα/2 = 0.03/√0.75 * 0.25/500 </em>
<em>= 1.549</em>
<em>Now,</em>
<em>Ф (1.549) = 0.9394</em>
<em>Therefore the confidence level becomes:</em>
<em> 1- (1-∝)/2 = 0.9394</em>
<em>∝ = 0.8788</em>
<em>The answer is 0.8788</em>
<em />
The answer is k=8 (4,6/8,7/12,8)
Ally ran 5 miles in 36 minutes.
Ally's speed is (5 miles)/(36 minutes) = 0.13888 miles per minute.
At that speed, Ally would run 6 miles in (6 miles)/(0.13888 miles/min) = 43.2 minutes.
Ally runs faster than Sami, so Sami must take longer to run 6 miles than Ally.
The only time that is longer than 43.2 minutes is 48 minutes.
Answer:
a) v = 12.21m/s
a = 4.07 m/s²
b)v = 11.24m/s
a = 3.75 m/s²
Step-by-step explanation:
a) Dividing the moviment into two parts:
I - With acceleration
v = v₀ + at
s = s₀ + v₀t + at²/2
- v₀ = 0
- s₀ = 0
- a = ?
- v = ?
- t = 3s
- s = x
v = v₀ + at
v = 3a ⇒ a = v/3
s = s₀ + v₀t + at²/2
x = v/3.3²/2
x = 3v/2
II - Uniform
s = s₀ + vt
s = 100
s₀ = x
v = v
t = 9.69 - 3 = 6.69s
s = s₀ + vt
100 = x + v*6.69
100 = x + 6.69v
As x = 3v/2
100 = 3v/2 + 6.69v
100 = 1.5v + 6.69v
100 = 8.19v
v = 12.21m/s
a = v/3 = 4.07 m/s²
b) Dividing the moviment into two parts:
I - With acceleration
v = v₀ + at
s = s₀ + v₀t + at²/2
- v₀ = 0
- s₀ = 0
- a = ?
- v = ?
- t = 3s
- s = x
v = v₀ + at
v = 3a ⇒ a = v/3
s = s₀ + v₀t + at²/2
x = v/3.3²/2
x = 3v/2
II - Uniform
s = s₀ + vt
s = 200
s₀ = x
v = v
t = 19.30 - 3 = 16.30s
s = s₀ + vt
200 = x + v*16.3
100 = x + 16.3v
As x = 3v/2
200 = 3v/2 + 16.3v
200 = 1.5v + 16.3v
200 = 17.8v
v = 11.24m/s
a = v/3 = 3.75 m/s²
