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3 years ago

Which data collections are considered a census? Select all that apply.

Mathematics

2 answers:

Leni [432]3 years ago

8 0

Answer: Choice B.

Step-by-step explanation:

Censuses are complete data collections of every member of a population.

For example, the U.S. Census occurs every 10 years and documents every member of the American population.

Choice A only surveys the first ten students; this is not a complete census.

Choice B surveys all the students in the targeted data group. This is a census.

Choice C only surveys the male students, even though there are female students in his data group. This is not a census.

Choice D only surveys the girls on the soccer team, even though there may be boys on the team as well. This is not a census.

Choice E only surveys his friends in the chorus, even though there may have been people that were not his close friends. This is not a census.

Only choice B is a complete census.

marin [14]3 years ago

4 0

Answer:

choice B

Step-by-step explanation:

because choice b is the only complete census

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Let C(n, k) = the number of k-membered subsets of an n-membered set. Find (a) C(6, k) for k = 0,1,2,...,6 (b) C(7, k) for k = 0,

vladimir1956 [14]

Answer:

(a) $C(6,0) = 1$ , $C(6,1) = 6$ , $C(6,2) = 15$ , $C(6,3) = 20$ , $C(6,4) = 15$ , $C(6,5) = 6$ , $C(6,6) = 1$ .

(b) $C(7,0) = 1$ , $C(7,1) = 7$ , $C(7,2) = 21$ , $C(7,3) = 35$ , $C(7,4) = 35$ , $C(7,5) = 21$ , $C(7,6) = 7$ , $C(7,7)=1$ .

Step-by-step explanation:

In this exercise we only need to recall the formula for C(n,k):

$C(n,k) = \frac{n!}{k!(n-k)!}$

where the symbol $n!$ is the factorial and means

$n! = 1\cdot 2\cdot 3\cdot 4\cdtos (n-1)\cdot n$ .

By convention 0!=1. The most important property of the factorial is $n!=(n-1)!\cdot n$ , for example 3!=1*2*3=6.

(a) The explanations to the solutions is just the calculations.

$C(6,0) = \frac{6!}{0!(6-0)!} = \frac{6!}{6!} = 1$

$C(6,1) = \frac{6!}{1!(6-1)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,2) = \frac{6!}{2!(6-2)!} = \frac{6!}{2\cdot 4!} = \frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,3) = \frac{6!}{3!(6-3)!} = \frac{6!}{3!\cdot 3!} = \frac{5!\cdot 6}{6\cdot 6} = \frac{5!}{6} = \frac{120}{6} = 20$

$C(6,4) = \frac{6!}{4!(6-4)!} = \frac{6!}{4!\cdot 2!} = frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,5) = \frac{6!}{5!(6-5)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,6) = \frac{6!}{6!(6-6)!} = \frac{6!}{6!} = 1$ .

(b) The explanations to the solutions is just the calculations.

$C(7,0) = \frac{7!}{0!(7-0)!} = \frac{7!}{7!} = 1$

$C(7,1) = \frac{7!}{1!(7-1)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,2) = \frac{7!}{2!(7-2)!} = \frac{7!}{2\cdot 5!} = \frac{6!\cdot 7}{2\cdot 5!} = \frac{5!\cdot 6\cdot 7}{2\cdot 5!} = \frac{6\cdot 7}{2} = 21$

$C(7,3) = \frac{7!}{3!(7-3)!} = \frac{7!}{3!\cdot 4!} = \frac{6!\cdot 7}{6\cdot 4!} = \frac{5!\cdot 6\cdot 7}{6\cdot 4!} = \frac{120\cdot 7}{24} = 35$

$C(7,4) = \frac{7!}{4!(7-4)!} = \frac{6!\cdot 7}{4!\cdot 3!} = frac{5!\cdot 6\cdot 7}{4!\cdot 6} = \frac{120\cdot 7}{24} = 35$

$C(7,5) = \frac{7!}{5!(7-2)!} = \frac{7!}{5!\cdot 2!} = 21$

$C(7,6) = \frac{7!}{6!(7-6)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,7) = \frac{7!}{7!(7-7)!} = \frac{7!}{7!} = 1$

For all the calculations just recall that 4! =24 and 5!=120.

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Answer:

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3 years ago

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ehidna [41]

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Step-by-step explanation:

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3 years ago

Using complete sentences, explain the differences between an expression and an equation I need it asap

borishaifa [10]

Answer:

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Step-by-step explanation:

That was the step-by-step explanation. <3

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3 years ago

Read 2 more answers

3. Red candy costs $2.50 per pound. Green candy costs $4.75 per pound. You bought ten pounds of candy for $38.50. How many pound

Aloiza [94]

Answer:

6 pounds of green candy

Step-by-step explanation:

Let r be the weight of red candy

Let g be the weight of green candy

Total weight = 10 pounds

r + g = 10 -------------------------(I)

Total cost = $ 38.50

2.50r + 4.75g = 38.50 --------------(II)

Multiply equation (I) by -2.50

(I)* (-2.50) -2.50r - 2.50g = -25.0

(II) 2.50r + 4.75g = 38.50 {Now add and r will be eliminated}

2.25g = 13.50

g =13.50/2.25

g = 6

Plug in the value of g in equation (I)

r + 6 = 10

r = 10 - 6

r = 4

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4 years ago