(x + y)^2 = (x^2 - 2xy + y^2)
First distribute the ^2 on the left side of the equation to each term inside the parenthesis:
x^2+ 2xy + y^2
Now pick one of the variables to solve for and isolate it:
(solving for x)
x^2 + 2xy + y^2 = x^2 - 2xy + y^2
x^2+ 2xy = x^2 - 2xy
2xy = -2xy
-x = x
x = 0
When you solve for y in the equation it will turn out to be 0 as well
To solve<span> a logarithmic equation, rewrite the equation in exponential form and </span>solve<span>for the variable</span>
Answer:
I think it's B. 5/9(F -32) < 140
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50
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Answer:
Ask your Teacher if you are missing any work and if you are do it and do some things for extra credit
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