The length of ST is 10 units, the length of S't" is 2 units.
This means the dilated figure was decreased by a factor of 5.
Because it is smaller it would be a scale factor of 1/5 ( 0.2 as a decimal).
Zero.
Anything times zero is zero.
-20 * -10 = 200
200 * -1 = -200
-200 * 0 = 0
I believe 10% because 390 and 39 are exactly the same numbers almost
The parametric equations for x and y describe a circle of radius 10 m, so the length of the base of the fence is the length of the circumference of a circle of radius 10 m. The formula for that circumference (C) is ...
... C = 2πr
... C = 2π·(10 m) = 20π m
The height as a function of angle (t) is found by substituting for x and y.
... h(t) = h(x(t), y(t)) = 4 + 0.01·((10cos(t))²-)10sin(t))²) = 4+cos(2t)
The average value of this over the range 0 ≤ t ≤ 2π is 4, since the cosine function has two full cycles in that range, and its average value over a cycle is zero.
Thus, the area of one side of the fence is that of a rectangle 20π m long and 4 m wide. That will be
... (20π m)·(4 m) = 80π m²
The amount of paint required to cover both sides of the fence is
... 2×(80π m²)×(1 L)/(10 m²) = 16π L ≈ 50.3 L
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You can work out the integral for area as a function of t. When you do, you will find it gives this same result.
1. Equation: 4x + 6y = 40
Answer:!4x + 6y - 40 = 0
2x + 3y - 20 = 0
2. Equation: 2x + 6y = 26
Answer: 2x + 6y - 26 = 0
x + 3 y - 13 = 0
