Answer:
(a) See attachment
(b) Mara's rectangle
Step-by-step explanation:
Given
Mara
![Area =15cm^2](https://tex.z-dn.net/?f=Area%20%3D15cm%5E2)
Ashton
![Area =9cm^2](https://tex.z-dn.net/?f=Area%20%3D9cm%5E2)
Solving (a): Draw the rectangles
First, we need to calculate the possible dimension of both rectangles.
Area is calculated as:
![Area = Length * Width](https://tex.z-dn.net/?f=Area%20%3D%20Length%20%2A%20Width)
For Mara
![15 = Length * Width](https://tex.z-dn.net/?f=15%20%3D%20Length%20%2A%20Width)
Possible values of length and width are:
![Length = 5cm](https://tex.z-dn.net/?f=Length%20%3D%205cm)
![Width = 3cm](https://tex.z-dn.net/?f=Width%20%3D%203cm)
This is so because:
![5cm * 3cm = 15cm^2](https://tex.z-dn.net/?f=5cm%20%2A%203cm%20%3D%2015cm%5E2)
For Ashton
![9 = Length * Width](https://tex.z-dn.net/?f=9%20%3D%20Length%20%2A%20Width)
Possible values of length and width are:
![Length = 4.5cm](https://tex.z-dn.net/?f=Length%20%3D%204.5cm)
![Width = 2cm](https://tex.z-dn.net/?f=Width%20%3D%202cm)
This is so because:
![4.5cm * 2cm = 9cm^2](https://tex.z-dn.net/?f=4.5cm%20%2A%202cm%20%3D%209cm%5E2)
<em>See attachment for diagram</em>
Solving (b): Rectangle with bigger area
Mara's rectangle has a bigger area because ![15cm^2 > 9cm^2](https://tex.z-dn.net/?f=15cm%5E2%20%3E%209cm%5E2)
Answer:
i think the answer is 8
Step-by-step explanation:
"three less than the quotient of 6 and a number (n=3) increased by nine"
(6÷3)-3+9
the quotient of 6 and 3 (6÷3) is 2
three less than 2: 2-3 which equals -1
increased by nine: -1+9 (which is also the same as 9-1) is 8
please don't hesitate to ask for clarification! hope i helped!
Budget for your needs before your wants :)
meaning, if you need new tires on your car, but you would like to have a new iphone (there's nothing wrong with the one you have), you should budget so that you have enough to pay for your tires and then whatever spare money you have leftover, you can use for the iphone :)
Answer:
Just find the area of each of them
Step-by-step explanation:
G(f(1))
Plug 1 into the f function.
f(1) = 2(1) + 6
f(1) = 8
Now evaluate g(8)
g(8) = 8^2 + 6
g(8) = 70