Answer:
size of small rectangle ( 10.15)
size of large rectangle ( 15 , 20 )
Step-by-step explanation:
Let the small rectangle have length x and breadth y . Let the larger rectangle have length x + 5 and breadth y + 5
perimeter of small rectangle = 2 ( x + y )
perimeter of large rectangle = 2 ( x + y + 10 )
= 2( x + y ) + 20
difference = 20
Now area of small rectangle = xy
area of large rectangle = ( x + 5 ) ( y + 5 )
given ( x + 5 ) ( y + 5 ) = 2 xy
xy + 5 ( x + y ) + 25 = 2xy
5 ( x + y ) + 25 = xy
finding the solution of this equation by trial and error
put x = 10 and y = 15
5 ( 10 + 15 ) + 25 = 150
xy = 10 x 15 = 150
so,
x = 10 , y = 15
size of large rectangle
= 10 + 5 = 15 and
15 + 5 = 20
size of small rectangle ( 10.15)
size of large rectangle ( 15 , 20 )
