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Aneli [31]
3 years ago
8

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Mathematics
1 answer:
julia-pushkina [17]3 years ago
4 0
19929299:93992929292
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2. Mrs. Long just got a new puppy! The puppy is learning how to run on hard wood floors. The puppy is running at a rate if 4 fee
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1.The puppy will run into the wall after 5 seconds

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4 years ago
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you should spend one week worth of pay on rent. she makes 32,000 a year. what is max she should spend
deff fn [24]

Hi!


We know she makes $32,000 a year, but we need to know how much she makes in a week. Which leads us to the question,"How many weeks are in a year?".


There are about 52 weeks in a year.


To found out how much money she makes per week, divide.


money per week

32000/52 = 615.384615


I'm not sure if they want you to round up, or round down, or what, but the exact answer is 615.384615.


Hope this helps! :) -Peredhel

8 0
3 years ago
Real solutions please WILL GIVE BRAINLIEST
Svetllana [295]

Answer:

the answer is A=2

Step-by-step explanation:

a real solution is a solution that uses real numbers. This equation has 2 real solutions.

6 0
3 years ago
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the dimensions of a rectangle are given in terms of X as shown below the perimeter of the rectangle is 7 3/5 units. what is the
stepan [7]

Answer:

it is 8.65

Step-by-step explanation:

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4 0
3 years ago
La probabilidad de que el estudiante A apruebe un examen de MM-100 es 0.6, la probabilidad de que apruebe un estudiante B es 0.4
ivanzaharov [21]

Answer:

0.5 = 50% probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.

Step-by-step explanation:

La probabilidad condicional :

P(B|A) = \frac{P(A \cap B)}{P(A)}

En el cual:

P(B|A) es la probabilidad de que ocurra el evento B, dado que A sucedió.  

P(A \cap B) es la probabilidad de que ocurran tanto A como B.  

P(A) es la probabilidad de que ocurra A.

En esta pregunta :

Evento A: Estudiante A aprueba.

Evento B: Estudiante B aprueba.

La probabilidad de que el estudiante A apruebe un examen de MM-100 es 0.6

Entonces P(A) = 0.6

La probabilidad de que ambos estudiantes aprueben es 0.3

Entonces P(A \cap B) = 0.3

¿Cual es la probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3}{0.6} = 0.5

0.5 = 50% probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.

6 0
3 years ago
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