Answer:
f(x) = (x - 7)² - 14
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
- Standard Form: ax² + bx + c = 0
- Vertex Form: f(x) = a(bx - c)² + d
- Completing the Square: (b/2)²
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = x² - 14x + 63
<u>Step 2: Rewrite</u>
- Separate: f(x) = (x² - 14x) + 63
- Complete the Square: f(x) = (x² - 14x + 49) + 63 - 49
- Simplify: f(x) = (x - 7)² - 14
Answer:
C. 272
Step-by-step explanation:
Since we know 85% of the students participated last year we can assume the same amount will participate this year so to find the answer you simply do the total number of students (320) multiplied by 85% or .85 to get the best guess of how many students will participate this year.
Answer:
1. 10x^2 -4
2. 2a^5 + 5b
Step-by-step explanation:
1. Simplify 4(x^2 -1) to 4x^2 -4
then add that to 6x^2
2. 4a^5 - 2a^5 = 2a^5 and
4b+b = 5b
Answer:
155.3 m
Step-by-step explanation:
<u>We have:</u>
θ: is the angle measured from the vertical = 75 °
v = is the speed of the submarine = 10 m/s
t = 1 min
The deep of the front end of the submarine at the end of a 1-minute drive is given by the following ratio:
<u>Where:</u>
d: is the distance traveled by the submarine in 1 minute
x: is the deep to find
The distance, d, is:
Now, the deep is:
Therefore, the deep of the front end of the submarine at the end of a 1-minute drive is 155.3 m.
I hope it helps you!
