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MrMuchimi
3 years ago
15

Convert 7.82km to centimeters and 4871 mm to centimeters​

Mathematics
1 answer:
nasty-shy [4]3 years ago
4 0

Answer:

7.82km = 782000cm

4871mm = 487.1

For the Millimeter one you divide the length value by 10 and for the kilometer one you multiply the length value by 100000.

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Solve the equation x2 - 6x + 5 = 0 by graphing the related function.
Neko [114]

Answer:

The solutions are 1 and 5.

Step-by-step explanation:

x2 − 6x + 5 = 0

Step 1: Write the related function.

x2 − 6x + 5 = 0

y = x2 − 6x + 5

Step 2: Graph the function.

Use a graphing calculator.

Step 3: Find the zeros.

The zeros are 1 and 5.

7 0
3 years ago
The lengths of pregnancies in a small rural village are normally distributed with a mean of 264.1 days and a standard deviation
KiRa [710]

Answer:

The range of the 95% data (X) =  238.3 days <  X < 289.9 days

Step-by-step explanation:

Given;

mean of the normal distribution, m = 264.1 days

standard deviation, d = 12.9 days

between two standard deviation below and above the mean is 96% of all the data.

two standard deviation below the mean = m - 2d

                                                                   = 264.1 - 2(12.9)

                                                                   = 238.3 days

two standard deviation above the mean = m + 2d

                                                                    = 264.1 + 2(12.9)

                                                                     = 289.9 days

The middle of the 95% of most pregnancies would be found in the following range;

238.3 days <  X < 289.9 days

5 0
3 years ago
Laura left Dunkin Donuts at 1 PM traveling 30 mph. Two hours later her friend Jen left the same Dunkin Donuts and started after
Wewaii [24]

Answer:

It took Jen 4 hours to catch up with Laura

Step-by-step explanation:

Gaining speed 45-30= 15 mph

Laura's head start 30×2=60 miles

Time for Jen to catch up 60÷15= 4 hours

In other words

30(t+2)= 45t

30t+60= 45t

60=45t-30t

60= 15t

t=4 hours

5 0
3 years ago
What are compatible numbers?
posledela
Numbers that are close in value to the actual numbers.
4 0
3 years ago
Read 2 more answers
Find positive numbers x and y satisfying the equation xyequals12 such that the sum 4xplusy is as small as possible. Let S be the
WITCHER [35]

Answer:

The objective function in terms of one​ number, x is

S(x) = 4x + (12/x)

The values of x and y that minimum the sum are √3 and 4√3 respectively.

Step-by-step explanation:

Two positive numbers, x and y

x × y = 12

xy = 12

S(x,y) = 4x + y

We plan to minimize the sum subject to the constraint (xy = 12)

We can make y the subject of formula in the constraint equation

y = (12/x)

Substituting into the objective function,

S(x,y) = 4x + y

S(x) = 4x + (12/x)

We can then find the minimum.

At minimum point, (dS/dx) = 0 and (d²S/dx²) > 0

(dS/dx) = 4 - (12/x²) = 0

4 - (12/x²) = 0

(12/x²) = 4

4x² = 12

x = √3

y = 12/√3 = 4√3

To just check if this point is truly a minimum

(d²S/dx²) = (24/x³) = (8/√3) > 0 (minimum point)

4 0
3 years ago
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