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2 years ago

What is the slope and the y-intercept of the linear function that is represented by the graph

Mathematics

1 answer:

alex41 [277]2 years ago

8 0

Slope is Y=2/3x-2
Y intercept is -2

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What is the value of h

Marta_Voda [28]

I believe it would be 0 fr

8 0

2 years ago

(x^2-2)^2-10(x^2-2)+21=0 find one value of x that is a solution to the equation

Sloan [31]

Answer:

x=3; x=-3; x=√5; x=-√5

Step-by-step explanation:

6 0

3 years ago

For the function f(x)=3xsquared- 2x+5 find f(1) f(-2) and f(a)

Oksanka [162]

$f(x)=3x^2-2x+5\\\\
f(1):\ \ Substitude\ 1 \ as\ x\ into\ function:\\
f(1)=3*1^2-2*1+5=3-2+5=\textbf{6}\\\\
f(-2)\ \ Substitude\ x=-2\\
f(-2)=3*(-2)^2-2*(-2)+5=3*4+4+5=12+4+5=\textbf{21}\\\\
f(a)\ \ substitude\ x=a\\
f(a)=\underline{3a^2-2a+5}$

4 0

3 years ago

I'm having trouble with #2. I've got it down to the part where it would be the integral of 5cos^3(pheta)/sin(pheta). I'm not sur

Butoxors [25]

$\displaystyle\int\frac{\sqrt{25-x^2}}x\,\mathrm dx$

Setting $x=5\sin\theta$ , you have $\mathrm dx=5\cos\theta\,\mathrm d\theta$ . Then the integral becomes

$\displaystyle\int\frac{\sqrt{25-(5\sin\theta)^2}}{5\sin\theta}5\cos\theta\,\mathrm d\theta$
$\displaystyle\int\sqrt{25-25\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$
$\displaystyle5\int\sqrt{1-\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$
$\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$

Now, $\sqrt{x^2}=|x|$ in general. But since we want our substitution $x=5\sin\theta$ to be invertible, we are tacitly assuming that we're working over a restricted domain. In particular, this means $\theta=\sin^{-1}\dfrac x5$ , which implies that $\left|\dfrac x5\right|\le1$ , or equivalently that $|\theta|\le\dfrac\pi2$ . Over this domain, $\cos\theta\ge0$ , so $\sqrt{\cos^2\theta}=|\cos\theta|=\cos\theta$ .

Long story short, this allows us to go from

$\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$

to

$\displaystyle5\int\cos\theta\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$
$\displaystyle5\int\dfrac{\cos^2\theta}{\sin\theta}\,\mathrm d\theta$

Computing the remaining integral isn't difficult. Expand the numerator with the Pythagorean identity to get

$\dfrac{\cos^2\theta}{\sin\theta}=\dfrac{1-\sin^2\theta}{\sin\theta}=\csc\theta-\sin\theta$

Then integrate term-by-term to get

$\displaystyle5\left(\int\csc\theta\,\mathrm d\theta-\int\sin\theta\,\mathrm d\theta\right)$
$=-5\ln|\csc\theta+\cot\theta|+\cos\theta+C$

Now undo the substitution to get the antiderivative back in terms of $x$ .

$=-5\ln\left|\csc\left(\sin^{-1}\dfrac x5\right)+\cot\left(\sin^{-1}\dfrac x5\right)\right|+\cos\left(\sin^{-1}\dfrac x5\right)+C$

and using basic trigonometric properties (e.g. Pythagorean theorem) this reduces to

$=-5\ln\left|\dfrac{5+\sqrt{25-x^2}}x\right|+\sqrt{25-x^2}+C$

4 0

2 years ago

Read 2 more answers

What is theformula for finding the hight of a 30-60-90 degree triangle

miv72 [106K]

We don't know which side your triangle is sitting on, so the 'height'
could be any one of three values.

Here are the two simple tools that tell you everything you want to
know about a 30°-60°-90° triangle. These are worth memorizing:

-- The side opposite the 30° angle is 1/2 of the hypotenuse.

-- The side opposite the 60° angle is 1/2 of the hypotenuse times √3 .

I memorized them exactly 60 years ago. They've been very useful,
and as far as I know, they haven't changed.

7 0

3 years ago