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Goryan [66]
3 years ago
11

An athletics squad trains on a long straight track with dots marked at 10m intervals. The coach sets out cones on some of the do

ts for the squad's sprint training drills. She wants the squad to be able to run any distance which is a multiple of 10m, up to some maximum distance which depends on the number of cones.
Explain why it is not possible to place four cones A, B, C, D, in a line so that each multiple of 10m up to 70m can be run between two of the cones.
Mathematics
1 answer:
Sedaia [141]3 years ago
8 0

Answer:

There are 6 ways to run 10 m between two cones of the four cones giving a maximum available distance to run as 60 meters

Step-by-step explanation:

The parameters given are

Distance between two cones = 10 m

Number of cones = 4

Therefore, number of ways to choose two 10 m distances (distance between two cones) from the four cones = \binom{4}{2} = 6

Hence there are only six 10 m distances to run between two cones which gives a maximum distance available to run as 60 m.

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200g plain flour

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The volume of a right circular cylinder is 1100 cm3 and the radius of its base is 5 cm. Calculate its curved surface area.
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Step-by-step explanation:

<u>Volume:</u>

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Can someone help me please
kifflom [539]

9514 1404 393

Answer:

  {Segments, Geometric mean}

  {PS and QS, RS}

  {PS and PQ, PR}

  {PQ and QS, QR}

Step-by-step explanation:

The three geometric mean relationships are derived from the similarity of the triangles the similarity proportions can be written 3 ways, each giving rise to one of the geometric mean relations.

  short leg : long leg = SP/RS = RS/SQ   ⇒   RS² = SP·SQ

  short leg : hypotenuse = RP/PQ = PS/RP   ⇒   RP² = PS·PQ

  long leg : hypotenuse = RQ/QP = QS/RQ   ⇒   RQ² = QS·QP

I find it easier to remember when I think of it as <em>the segment from R is equal to the geometric mean of the two segments the other end is connected to</em>.

__

  segments PS and QS, gm RS

  segments PS and PQ, gm PR

  segments PQ and QS, gm QR

4 0
3 years ago
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