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TEA [102]
2 years ago
7

Factor completely.28 - 7x^2 ​

Mathematics
1 answer:
FrozenT [24]2 years ago
8 0

Answer:

7(4 - x^2)

Step-by-step explanation:

Well you just factor out 7, since that is the GCF. 7(4 - x^2)

Hope this helps

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If T (n) =6-1 what is the 1st term.
Mariulka [41]
T(n)=6-1=5
that means all terms are 5 because n does not appear on the right hand side.

However, if T(n)=6n-1, then
first term = T(1)=6(1)-1=5,
but second term T(2)=6(2)-1=11...
8 0
3 years ago
How would you correctly write the equation 4(10+5)=6(12-2) using the distributive property?
slamgirl [31]

the correct answer is 45=70

3 0
3 years ago
A car rental company charges a daily rate of $ 23 plus $ 0.20 per mile for a certain car. Suppose that you rent that car for a d
MAXImum [283]

Answer: 105 miles?

I am not sure but that"s what I got

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Alan bought a suit on sale for $208. This price was 35% less than the original price.
algol [13]

Answer:

280.8

Step-by-step explanation:

Since 100% is the full amount, and it is 35% off you add 35 to the 100. So you get 1.35. You finally multiply by 207 and get 280.8

7 0
3 years ago
The angle of depression from a helicopter to a landing pad is 37 degrees. if the helicopter is 1250 feet from the ground. what i
djyliett [7]

The horizontal distance from the helicopter to the landing pad is 1658.81 feet

<em><u>Solution:</u></em>

The figure is attached below

Triangle ABC is a rightangled triangle

A helicopter is flying at point A and landing pad is at point c

Angle of depression of the helicopter is 37 degrees so angle of elevation of this helicopter from landing pad will be same as 37 degrees

The helicopter is 1250 feet from the ground

Therefore, AB = 1250 feet

To find: horizontal distance from the helicopter to the landing pad

BC is the horizontal distance from the helicopter to the landing pad

BC = ?

By the definition of tan,

tan \theta = \frac{opposite}{adjacent}

tan 37 = \frac{AB}{BC}\\\\tan 37 = \frac{1250}{BC}\\\\ 0.75355 = \frac{1250}{BC}\\\\BC = \frac{1250}{0.75355}\\\\BC = 1658.81

Thus the horizontal distance from the helicopter to the landing pad is 1658.81 feet

5 0
3 years ago
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