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Marysya12 [62]
3 years ago
5

Dimitri is helping to plan the school talent show. Each performer for the talent show has 6 66 minutes for his or her performanc

e, which includes transition time between performances. If the introduction for the talent show is 2 4 2424 minutes long and the entire show, including the introduction, will last 1 5 0 150150 minutes, how many different performances can the talent show accommodate?
Mathematics
1 answer:
antoniya [11.8K]3 years ago
7 0
The talent show consists of introduction and talent performance. It could be written into this equation
Talent show duration= introduction + talent performance

Each performer for the talent show has 6 minutes for their show, the <span>introduction of the talent show is 24 minutes, and the total duration should be 150 minutes. Then, maximum performance count of the show would be:
</span>
Talent show duration= introduction + talent performance
<span>150 min = 24 min + (performance count * 6min)
</span>performance count = (150min - 24min) / 6 min
performance count=21
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Step-by-step explanation:

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On a coordinate plane, a rectangle is shown with points S (4, negative 4), R (4, negative 10), Q (negative 7, negative 10), and
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Answer:

The coordinates of the image of vertex P after reflection is  (-7, 4)

Step-by-step explanation:

Given that we are to reflect the point P across the x-axis, we have;

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Read 2 more answers
Segment PH is graphed on the coordinate grid where P is (-31,8) and H is (29,-10). Point E is the midpoint of segment PH. If poi
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Answer:

The coordinates of point A are (-11 , 2)

Step-by-step explanation:

- The coordinates of point P are (-31 , 8)

- The coordinates of point H are (29 , -10)

- Point E is the mid-point of segment PH

- The coordinates of the the mid-point are:

→ x=\frac{x_{1}+x_{2}}{2} and y=\frac{y_{1}+y_{2}}{2}

∵ E is the mid-point of segment PH

∴ The x-coordinate of point E is x=\frac{-31+29}{2}=-1

∴ The x-coordinate of point E is -1

∴ The y-coordinate of point E is y=\frac{8+-10}{2}=-1

∴ The y-coordinate of point E is -1

∴ The coordinates of point E are (-1 , -1)

- Point A is graphed \frac{2}{3} of the way along the segment from P to E

- That mean the distances from points P to A is 2 parts and from P to E

  is 3 parts, then the distance from A to E is "3 - 2" = 1 part

- So point A divides the line segment PE at ratio 2 : 1 from P

- The coordinates of the division point are:

→ x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}} and y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}

∵ Point A divides PE at ratio 2 : 1

∵ The coordinates of point P are (-31 , 8)

∵ The coordinates of point E are (-1 , -1)

∴ The x-coordinate of point A is x=\frac{(-31)(1)+(-1)(2)}{2+1}= -11

∴ The x-coordinate of point A is -11

∴ The y-coordinate of point A is x=\frac{(8)(1)+(-1)(2)}{2+1}=2

∴ The y-coordinate of point A is 2

∴ The coordinates of point A are (-11 , 2)

* The coordinates of point A are (-11 , 2)

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3 years ago
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Answer:

answer is 0 meaning there is no solution

Step-by-step explanation:

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