3 years ago

Do these side lengths make a right triangle? 6.4, 12, 12.2

Mathematics

1 answer:

Marrrta [24]3 years ago

8 0

No.
Square root of 6.4^2 + 12^2 is larger than 12.2

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Multiply (2.5x10^-10) (7x10^-6)

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We want to multiply $2.5\cdot10^{-10}$ by $7\cdot10^{-6}$ .

The numbers are written in scientific notation. So we expect the answer also to be in scientific notation.

the multiplication of the 10's, using the exponents rule is :

$10^{-10}\cdot 10^{-6}=10^{-10+(-6)}=10^{-10-6}=10^{-16}$

the multiplication of the other 2 numbers is:

$2.5\cdot7=17.5=1.75\cdot10$

(we write the number so that it has only one digit to the left of the decimal point).

Thus,

$(2.5\cdot10^{-10})\cdot(7\cdot10^{-6})=1.75\cdot10\cdot10^{-16}=1.75\cdot10^{-15}$

Answer: $1.75\cdot10^{-15}$

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