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3 years ago

-22m-13ni need to factorise this

Mathematics

1 answer:

sukhopar [10]3 years ago

7 0

1 22. 1 13
11 22. 13 13
22 22

answer 1 (-22m -13n)

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Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

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1 year ago

Please help!!! I’m very desperate I’ll give brainliest!!

IgorC [24]

Answer:

question 22 ) 3.325

Step-by-step explanation:

I use the app photo math. Its free and shows you all the steps.

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2 years ago

Mrs. Payne needs 35 notepads she can buy them in packs of 10 notepads or a single pads what are all the different ways of Mrs. P

castortr0y [4]

Ok she can buy 1 ten and 25 ones, 2 tens 15 ones, 3 tens 5 ones, and 35 ones. (Pretty sure)

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3 years ago

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Simplify the expression 7(3+2p+7).

ipn [44]

Answer: 14p +70

Step-by-step explanation:

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2 years ago

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PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!

aleksley [76]

The length of PR is 4.4 units.

Explanation:

It is given that the length of the hypotenuse is 10 units.

Also, the angle of R is 64°

To find the length of PR, we shall use the cosine formula,

$\cos \theta=\frac{a d j}{h y p}$

Here, $\theta=64$ , adj = PR and hyp = 10

Substituting these values in the formula, we get,

$\cos 64=\frac{P R}{10}$

Multiplying both sides by 10, we get,

$10*\cos 64={P R}$

Substituting the value for cos 64, we get,

$10*0.438={P R}$

Multiplying, we have,

$4.38=PR$

Rounding off, we get,

$PR=4.4$

Thus, the length of PR is 4.4 units.

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3 years ago