In decimal it is:
0*8^0 + 7*8^1 + 4*8^2 + 2*8^3 = 1336
Basically adding up the place values.
Answer:
a)Yes Alice can pick 11 has value for her public exponent e
b) The value of d when the public exponent e = 3 is 37
c) The cipher c of the Bob’s message m =2 is 8
d) The cipher c of the Bob’s message m =3 is 18
e) The value of m if c = 3 and the public exponent e = 7 is 16
Explanation:
Find attached the explanation
Answer:
Means no matter how many processors you use, speed up never increase from 10 times.
Explanation:
If a problem of size W has a serial component Ws,then performance using parallelism:
Using Amdahl's Law:
Tp = (W - Ws )/ N + Ws
Here, Ws = .1,
W - Ws = .9
Performance Tp = (.9 / N) + .1
---------------------------------------------------------
Speed Up = 1 / ( (.9 / N) + .1)
If N -> infinity, Speed Up <= 10
Means no matter how many processors you use, speed up never increase from 10 times.
Answer:
Explanation:
The following code is written in Java, the function takes in a list with the previous day's values. The function then uses that list, loops through it and multiplies each individual value by 2 and returns the modified list. The first red square represents the test case for the function, while the second red square in the image represents the output.
public static ArrayList<Integer> doubleIt(ArrayList<Integer> mylist) {
for (int x = 0; x<mylist.size(); x++) {
mylist.set(x, mylist.get(x)*2);
}
return mylist;
}