Answer:
1) The initial value of the function is the y-value when the x-value is zero. The number of hours is the x-value and the percentage of battery life left is the y-value. When the number of hours, x, is 0, the percentage of remaining battery life, y, is 100 percent. So, the initial value of the function is 100. The initial value is positive because the percentage of remaining battery life cannot be negative.
2) The rate of change is the rate at which the y-value changes with respect to a change in the x-value. When off the charger, the phone loses its battery life at a constant rate of 5 percent per hour. So, the function’s rate of change is -5. The rate of change is negative because the rate indicates that the percentage of remaining battery life decreases as the number of hours increases.
Step-by-step explanation: I just did the tutorial right now i hope this helps
The formula in terms of h is h = 3V/s^2 and the value of h is 5
<h3>How to write the formula in terms of h?</h3>
The equation is given as
V = 1/3s^2h
Divide both sides of the equation by 1/3s^2
So, we have
h = 3V/s^2
The given parameters are
V = 60 and s = 6
So, we have:
h = 3 * 60/6^2
Evaluate
h = 5
Hence, the formula in terms of h is h = 3V/s^2 and the value of h is 5
Read more about formulas at:
brainly.com/question/10643782
#SPJ1
*115*
do the parentheses in the parentheses first, then the outer parentheses, then the stuff outside the parentheses.
PEMDAS
parentheses...exponents...multiplication/division...Addition/subtraction.
Answer:
<u><em>$4.50 or $4.5</em></u>
Step-by-step explanation:
<em><u>well, this is easy</u></em>
<em><u>30% equals to 0.30 right.</u></em>
<em><u>we can't divide because if we do then the answer would be 50$ and that's way more money than Jill has.</u></em>
<em><u>so your wondering. What do we do?</u></em>
<em><u>Well, what's 30% of 15?</u></em>
<em><u>It's 4.5</u></em>
<em><u>4 dollars and 5 cents that U will have with Jill.</u></em>
Is this simultaneous equations?
if yes then the first step is
make one of the unknown as the subject
