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3 years ago

Which results from a cross section made perpendicular to the base of a square pyramid? Check all that apply.

1 answer:

7 0

<span>ú </span>The square-shaped slice can be made from a slice parallel to the base of a right rectangular prism, cube, and right rectangular pyramid with a square base. The triangle-shaped slice and isosceles trapezoid-shaped slice can be made with a slice made perpendicular to the base of a right rectangular pyramid. A pentagon-shaped slice cannot be made from a slice made parallel or perpendicular to the base of either a right rectangular prism, right rectangular pyramid, or cube.

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Help???!!??????!??!!???!????!??

svet-max [94.6K]

$x_{vertex}= \frac{-2}{2 \cdot 3}=- \frac{2}{6}= - \frac{1}{3} \\\\\\ 
y_{vertex}=3 \cdot \left(- \frac{1}{3} \right)^2+2 \cdot \left(- \frac{1}{3} \right)+1=3 \cdot\frac{1}{9} - \frac{2}{3} +1=\frac{1}{3} - \frac{2}{3} +1= \frac{2}{3} \\ \\ \\ \boxed {\text {Answer:} \ \left(- \frac{1}{3}; \frac{2}{3} \right)}$

6 0

3 years ago

Gina has a jar of marbles that contains 7 blue marbles, 5 red marbles, and 8 green marbles. She randomly selects a marble, recor

BigorU [14]

The probability that Gina randomly selected two red marbles is 1/19

<u>Explanation:</u>

Total number of marbles = 7 + 5 + 8

= 20

The probability of getting two red marbles in the fraction form is given as:

P(first red marble) = number of red marbles / total number of marbles

P(first red marble) = $\frac{5}{20} = \frac{1}{4}$

P(second red marble) = number of red marbles after 1 white marble is removed / total number of marbles after 1 red marble is removed.

P(first red marble) = $\frac{4}{19}$

P(two red marbles) = P(first) X P(second)

= $\frac{1}{4} X \frac{4}{19}$

= $\frac{1}{19}$

Therefore, the probability that Gina randomly selected two red marbles is 1/19

6 0

3 years ago

An automobile manufacturer is concerned about a possible recall of its best selling four-door sedan. If there was a recall there

goldfiish [28.3K]

Complete question is;

An automobile manufacturer is concerned about a possible recall of its best - selling four-door sedan. If there were a recall, there is a probability of 0.25 of a defect in the brake system, 0.18 of a defect in the transmission, 0.17 of a defect in the fuel system, and 0.40 of a defect in some other area.

(a) What is the probability that the defect is the brakes or the fueling system if the probability of defects in both systems simultaneously is 0.15?

(b) What is the probability that there are no defects in either the brakes or the fueling system?

Answer:

A) 0.27

B) 0.73

Step-by-step explanation:

Let B denote that there is a defect in the break system

Let T demote that there is a defect in transmission

Let F denote that there is a defect in the fuel system.

Let P denote that there is a defect in some other area.

Now, we are given;

P(B) = 0.25

P(T) = 0.18

P(F) = 0.17

P(O) = 0.40

A) We are given that probability of defects in both brakes and the fueling system simultaneously is 0.15.

Thus, it means; P(B ⋂ F) = 0.15

Now, we want to find the probability that the defect is the brakes or the fueling system. This is expressed as;

P(B ⋃ F) = P(B) + P(F) - P(B ⋂ F)

Plugging in the relevant values to give;

P(B ⋃ F) = 0.25 + 0.17 - 0.15

P(B ⋃ F) = 0.27

B) We want to find the probability that there are no defects in either the brakes or the fueling system.

This is expressed as;

P(B' ⋃ F') = 1 - P(B ⋃ F)

Plugging in relevant value;

P(B' ⋃ F') = 1 - 0.27

P(B' ⋃ F') = 0.73

7 0

2 years ago

What is 2/5 times 6/7

OverLord2011 [107]

12/35 unless you simplify it

3 0

2 years ago

Read 2 more answers

Is 7/11 rational or irrational?

sattari [20]

The answers is Rational. hope that helps

8 0

3 years ago

Read 2 more answers