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3 years ago

Which results from a cross section made perpendicular to the base of a square pyramid? Check all that apply.

1 answer:

7 0

<span>ú </span>The square-shaped slice can be made from a slice parallel to the base of a right rectangular prism, cube, and right rectangular pyramid with a square base. The triangle-shaped slice and isosceles trapezoid-shaped slice can be made with a slice made perpendicular to the base of a right rectangular pyramid. A pentagon-shaped slice cannot be made from a slice made parallel or perpendicular to the base of either a right rectangular prism, right rectangular pyramid, or cube.

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Write the following number in standard form: 3.471 × 10^−5

muminat

0.00003471 is the correct answer I believe

4 0

3 years ago

If triangle PQR is similar to SQT, find the value of

ankoles [38]

Answer:

x = 31.4

PQ = 58.8

Step-by-step explanation:

Set up a proportion:

SQ/QP = ST/PR

Substitute in the values they give you:

$\frac{x-9}{x-9+x+5} = \frac{8}{21}$

$\frac{x - 9}{2x - 4} = \frac{8}{21}$

$21x - 189 = 16x - 32\\5x = 157\\x = 31.4$

This means that PQ = 2x - 4 = 2(31.4) - 4 = 62.8-4 = 58.8

5 0

3 years ago

Read 2 more answers

If the point (-6,4) is dialated by a scale factor of 1/2, what would be the resulting point

oksian1 [2.3K]

It depend on the center of the dilation. For example, if the point (-6,4) is the center itself, than it will remain the same.

If the dilation has the origin as center, instead, the factor 1/2 simply means that you have to divide all coordinates by 2: the point (-6,4) becomes the point (-3,2)

3 0

3 years ago

What should the following equation be multiplied by in order to eliminate the fractions? {2y}{3} + {1}{3} = {y}{2} + {1}{6}

Vika [28.1K]

Answer:

Multiply it by 25 :)

4 0

3 years ago

HELP PLS Given a polynomial function f(x), describe the effects on the Y-intercept, regions where the graph is increasing and de

Mashcka [7]

1. Remarks:

f(x) to f(x)-3 is the whole graph of f(x), shifted 3 units down.

f(x) to -2f(x):

The effect of "multiplication by -" is that the whole graph is reflected with respect to the x axis, so it is turned upside down.

The effect of "multiplication by 2" is that every point is "stretched vertically by a factor of 2" . So for example the point (-1, -4) in the original function, becomes (-1, -8) in the second one. Or (2, 5) would become (2, 10).

The only points that do not change (are not streched vertically) are the roots. For example if (4,0) is an x-intercept (a root) in the original function, (4,0) is still a root in the second one because 2 times 0 is still 0.

2. Consider the polynomial function of degree n:

$f(x)= a_{n} x^{n} +a_{n-1} x^{n-1}+....+a_{2} x^{2}+a_{1} x^{1}+a_{0}$

a. Y-intercept

The y - intercept is the value of the polynomial function at x=0.
So it is f(0)= $a_{0}$ , that is, the constant term of f(x)

in f(x)-3 the y intercept is shifted 3 units down as any other point, so it becomes $a_{0}-3$

In -2f(x), the y-intercept $a_{0}$ becomes $-2a_{0}$

b. Regions of f decreasing or increasing

f(x)-3 is f(x) just shifted down 3 units, so they are both increasing and decreasing in the same intervals of x

-2f(x) is f(x) turned upside down, so -2f(x) is increasing in all intervals f(x) is decreasing and it is decreasing in all intervals f(x) is increasing.

c. End behaviors

By now it is clear that end behaviors of f(x) and f(x)-3 are same, and f(x) with -2f(x) are opposite

d. Evenness, oddness

If f(x) is even, then f(x)=f(-x)

Let g(x)=f(x)-3

g(x)=f(x)-3=f(-x)-3=g(-3), so in this case f(x)-3 is even

If f(x) is odd, then f(-x)=-f(x)

g(x)=f(x)-3=-f(-x)-3,

so -g(x)=f(-x)+3

g(-x)=f(-x)-3,

so g(-x) is not equal to -g(x). Which means f(x)-3 is not odd if f(x) is

Consider f(x)=-2f(x)

If f(x) is even, f(x)=f(-x)

g(x)=-2f(x)=-2f(-x)
g(-x)=-2f(-x)

So g(x)=g(-x), which means -2f(x) is even if f(x) is even

If f(x) is odd, f(x)=-f(-x)

let g(x)=-2f(x)=-2(-f(-x))=2f(-x)

g(-x)=-2f(-x)=-2(-f(x))=2f(x)

so g(-x) is not equal to -g(x), thus -2f(x) is not odd if f(x) is odd.

The conclusions about oddness and evenness can be also derived from the discussions about the graphs.

6 0

3 years ago