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k0ka [10]
3 years ago
11

4(2x - 1) + 2x + 2 = 28

Mathematics
2 answers:
Artist 52 [7]3 years ago
8 0

Step-by-step explanation:

8x-4+2x+2=28

10x-2=28

10x=28+2

10x=30

x=3

lara31 [8.8K]3 years ago
3 0

Answer:

x=3

Step-by-step explanation:

isolate the variable by dividing each side by factors that dont contain the variable

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X+(x+1)+(×+2)=336. the question is the sum of three consecutive integers is 336​
vodomira [7]

Answer:

x = 111

Step-by-step explanation:

1.) x + (x + 1) + (x + 2) = 336

2.) x + x + 1 + x + 2 = 336

3.) 3x + 3 = 336

4.) 3x = 333

4.) x = 111

Check Work:

1.) 111 + (111 + 1) + (111 +2) = 336

2.) 111 + 111 + 1 + 111 + 2 = 336

3. ) 222 + 1 + 111 + 2 = 336

4.) 222 + 114 = 336

5.) 336 = 336

6 0
3 years ago
Solve the simultaneous equations<br> y = 9 - X<br> y = 2x2 + 4x + 6
kenny6666 [7]

Answer:

\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}

\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}

Step-by-step explanation:

Given the simultaneous equations

y=9-x

y\:=\:2x^2\:+\:4x\:+\:6

Subtract the equations

y=9-x

-

\underline{y=2x^2+4x+6}

y-y=9-x-\left(2x^2+4x+6\right)

\mathrm{Refine}

x\left(2x+5\right)=3

\mathrm{Solve\:}\:x\left(2x+5\right)=3

2x^2+5x=3        ∵ \mathrm{Expand\:}x\left(2x+5\right):\quad 2x^2+5x

\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}

2x^2+5x-3=3-3

\mathrm{Solve\:with\:the\:quadratic\:formula}

\mathrm{Quadratic\:Equation\:Formula:}

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=2,\:b=5,\:c=-3:\quad x_{1,\:2}=\frac{-5\pm \sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}v\\

x=\frac{-5+\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

  =\frac{-5+\sqrt{5^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

  =\frac{-5+\sqrt{49}}{2\cdot \:2}

  =\frac{-5+\sqrt{49}}{4}

  =\frac{-5+7}{4}

  =\frac{2}{4}

  =\frac{1}{2}

Similarly,

x=\frac{-5-\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}:\quad -3

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=\frac{1}{2},\:x=-3

\mathrm{Plug\:the\:solutions\:}x=\frac{1}{2},\:x=-3\mathrm{\:into\:}y=9-x

\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}\frac{1}{2}:\quad y=\frac{17}{2}

\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}-3:\quad y=12

\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}

\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}

3 0
4 years ago
Janelle had $12O when she went shopping. After she finished shopping she had$96. what is the percent decrease in her amount of m
Igoryamba
Left her \frac{96}{120}  = 0,8 = 80%
100% - 80% = 20%       <span>released 20 % of the amount</span>
7 0
3 years ago
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Answer:

y = -2x - 1

Step-by-step explanation:

y = -2x + b

3 = -2(-2) + b

3 = 4 + b

-1 = b

y = -2x - 1

6 0
3 years ago
Four transformations of the function f(x) = 2^x are given below.
Assoli18 [71]
6f(x) would be (6•2^x)
F(6x) would be 2^6x
F(x+6) would be 2^(x+6)
F(x)+6 would be (2^x)+6
5 0
2 years ago
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