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eimsori [14]
3 years ago
7

The perimeter of a square garden is 128m. Find the area of the garden in hectares?five star

Mathematics
1 answer:
aleksandrvk [35]3 years ago
7 0

Answer:

1024m

Step-by-step explanation:

128÷4=32

32×32=1024

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Which ratio does not belong with 2/6<br> a) 1/3 b) 3/9 c)6/15 d) 12/36
just olya [345]

Answer:

C)6/15

Step-by-step explanation:

it reduces to 2/5 no 1/3

12/36 --> 1/3

8 0
3 years ago
PLEASE HELP!!!!!!!!!
attashe74 [19]
Math homework, im excillent at math but dm me [email protected] and ill sent you the A

4 0
3 years ago
Suppose θ is an angle in the standard position whose terminal side is in Quadrant IV and cot θ= -6/7 . Find the exact values of
Llana [10]

Answer:

Part 1) csc(\theta)=-\frac{\sqrt{85}}{7}

Part 2) sin(\theta)=-\frac{7}{\sqrt{85}}  or sin(\theta)=-\frac{7\sqrt{85}}{85}

Part 3) tan(\theta)=-\frac{7}{6}

Part 4) cos(\theta)=\frac{6}{\sqrt{85}} or cos(\theta)=\frac{6\sqrt{85}}{85}

Part 5) sec(\theta)=\frac{\sqrt{85}}{6}

Step-by-step explanation:

we know that

The angle theta lie on the IV Quadrant

so

sin(θ) is negative

cos(θ) is positive

tan(θ) is negative

sec(θ) is positive

csc(θ) is negative

step 1

Find the value of csc(θ)

we know that

1+cot^{2}(\theta)=csc^{2}(\theta)

we have

cot(\theta)=-\frac{6}{7}

substitute

1+(-\frac{6}{7})^{2}=csc^{2}(\theta)

1+\frac{36}{49}=csc^{2}(\theta)

\frac{85}{49}=csc^{2}(\theta)rewrite

csc(\theta)=-\frac{\sqrt{85}}{7} ----> remember that is negative

step 2

Find the value of sin(θ)

we know that

csc(\theta)=\frac{1}{sin(\theta)}

we have

csc(\theta)=-\frac{\sqrt{85}}{7}

therefore

sin(\theta)=-\frac{7}{\sqrt{85}}

or

sin(\theta)=-\frac{7\sqrt{85}}{85}

step 3

Find the value of  tan(θ)

we know that

tan(\theta)=\frac{1}{cot(\theta)}

we have

cot(\theta)=-\frac{6}{7}

therefore

tan(\theta)=-\frac{7}{6}

step 4

Find the value of cos(θ)

we know that

sin^{2}(\theta)+cos^{2}(\theta)=1

we have

sin(\theta)=-\frac{7}{\sqrt{85}}

substitute

(-\frac{7}{\sqrt{85}})^{2}+cos^{2}(\theta)=1

\frac{49}{85}+cos^{2}(\theta)=1

cos^{2}(\theta)=1-\frac{49}{85}

cos^{2}(\theta)=\frac{36}{85}

cos(\theta)=\frac{6}{\sqrt{85}} ------> the cosine is positive

or

cos(\theta)=\frac{6\sqrt{85}}{85}

step 5

Find the value of sec(θ)

we know that

sec(\theta)=\frac{1}{cos(\theta)}

we have

cos(\theta)=\frac{6}{\sqrt{85}}

therefore

sec(\theta)=\frac{\sqrt{85}}{6} ----> is positive

8 0
4 years ago
Could someone pls help me out ???
professor190 [17]

Answer:

Option C.

Step-by-step explanation:

\sf\:x^{2}-3x+7=0

Use the biquadratic formula.

\sf\:\x=\frac{-\left(-3\right)(+/-)\sqrt{\left(-3\right)^{2}-4\times 7}}{2}

\sf\:x=\frac{-\left(-3\right)(+/-)\sqrt{9-4\times 7}}{2}

\sf\:x=\frac{-\left(-3\right)(+/-)\sqrt{9-28}}{2}

\sf\:x=\frac{-\left(-3\right)(+/-)\sqrt{-19}}{2}

\sf\:x=\frac{3(+/-)\sqrt{19}}{2}

Positive sign:

\boxed{\sf\:x=\frac{3+\sqrt{19}}{2}}

Negative sign:

\boxed{\sf\:x=\frac{3-\sqrt{19}}{2}}

Hope it helps ⚜

5 0
2 years ago
A health and fitness club surveys 40 randomly selected members and found that the average weight of those questioned is 157 lb.
svp [43]

Answer:

B. Statistic

Step-by-step explanation:

The average weight of those questioned which is 157 lb. from the survey of 40 randomly selected member of a health and fitness club is an example of a statistic.

It is a calculated numerical value that characterises some aspects of a sample set of data.

Statistic refers to a numerical piece of information that uses quantified models, representations and synopses for a given set of a study. Statistic is used to to estimate the true value of a parameter in a population.

6 0
3 years ago
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