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pashok25 [27]
3 years ago
5

Any one can help me please please I need help please each one 3 step explanation

Mathematics
1 answer:
Art [367]3 years ago
3 0

Answer:

a) Area of wall to be painted = 114 sq ft

b) Number of cans required = 2×5 = 10

c) Total cost of paint = $338.43

Step-by-step explanation:

<h2>Part a)</h2>

We are asked to find the area of wall that needs to be painted.

we need to subtract the area of window from the area of wall.

We know that area of a rectangular shape is given by

Area = Width×Length

Area of whole wall = 8×15 = 120 sq ft

Area of window = 2×3 = 6 sq ft

Area of wall to be painted = 120 - 6 = 114 sq ft

<h2>Part b)</h2>

1 can of paint will cover 25 sq ft of area.

So to cover the area of wall to be painted,

114/25 = 4.56

since number of cans cannot be in fraction so we would need 5 cans

Since two coats of paints are needed so

Number of cans required = 2×5 = 10

<h2>Part c)</h2>

1 can of paint costs $29.95

We have total 10 cans

$29.95×10 = $299.5

There is also a 13% tax so the total cost is

$299.5×0.13 = $38.93

Total cost of paint = $299.5 + $38.93

Total cost of paint = $338.43

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The equation of the tangent plane to the ellipsoid x2/a2 + y2/b2 + z2/c2 = 1 at the point (x0, y0, z0) can be written as xx0 a2
svetlana [45]

Answer:

The equation of tangent plane to the hyperboloid

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=1.

Step-by-step explanation:

Given

The equation of ellipsoid

\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1

The equation of tangent plane at the point \left(x_0,y_0,z_0\right)

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}+\frac{zz_0}{c^2}=1  ( Given)

The equation of hyperboloid

\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}{c^2}=1

F(x,y,z)=\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}[c^2}

F_x=\frac{2x}{a^2},F_y=\frac{2y}{b^2},F_z=-\frac{2z}{c^2}

(F_x,F_y,F_z)(x_0,y_0,z_0)=\left(\frac{2x_0}{a^2},\frac{2y_0}{b^2},-\frac{2z_0}{c^2}\right)

The equation of tangent plane at point \left(x_0,y_0,z_0\right)

\frac{2x_0}{a^2}(x-x_0)+\frac{2y_0}{b^2}(y-y_0)-\farc{2z_0}{c^2}(z-z_0)=0

The equation of tangent plane to the hyperboloid

\frac{2xx_0}{a^2}+\frac{2yy_0}{b^2}-\frac{2zz_0}{c^2}-2\left(\frac{x_0^2}{a^2}+\frac{y_0^2}{b^2}-\frac{z_0^2}{c^2}\right)=0

The equation of tangent plane

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Hence, the required equation of tangent plane to the hyperboloid

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=0

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3 years ago
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Answer:

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Hope this helps! :)

6 0
3 years ago
12.
Llana [10]

Answer:

9 Miles to be specific 8.95

Step-by-step explanation:

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4830 divided by 2700 = 1.78 m/s

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135 minutes X 60 seconds = 8100 secs

1.78 m/s X 8100 =14418 meters

14418 = 14.418 km

14.418 km = 9 miles

P.S. There is a shorter version but i think this is simpler for me and I use metric units.

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Step-by-step explanation:

:) ------------------

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