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klasskru [66]
3 years ago
7

Can someone help me with this math question!

Mathematics
2 answers:
marishachu [46]3 years ago
7 0

Answer:

0.5/2 is the constant rate of change

Step-by-step explanation:

lakkis [162]3 years ago
4 0

Answer:

Answer (RAC) + 2

Step-by-step explanation:

It starts at 0 increases by 2 eache time :)

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A trash can manufacturing company makes trash cans with the dimensions shown. They also make larger cans in which the radius and
fomenos
It is shown that by looking at the formula for the volume of a cylinder (we assume that the trash can is cylindrical):

V = pi*r^2*h

We can conclude that the volume of the trash can is directly proportional to its radius and height. To wrap up, the volume would increase as the radius of the trash can's base, and its height would be increased as well.
3 0
4 years ago
A maintenance technician sights the top of a telephone pole at a 25° angle of elevation as shown. Technician Telephone Pole Dete
Bumek [7]

Answer:

x = 375.3

Step-by-step explanation:

Given

See attachment for illustration

Required

Determine the horizontal distance

The horizontal distance is the distance between the technician and the base of the pole.

Represent this with x.

The relationship between x, 175ft and 25 degrees is represented as:

tan(25^{\circ}) = \frac{175}{x} --- i.e. tan formula

Multiply both sides by x

x * tan(25^{\circ}) = \frac{175}{x} * x

x * tan(25^{\circ}) = 175

Make x the subject

x = \frac{175}{tan(25^{\circ})}

x = \frac{175}{0.4663}

x = 375.294874544

x = 375.3 --- approximated

<em>The distance is approximately 375.3ft</em>

7 0
3 years ago
=
kenny6666 [7]

The cost to equip all the stations in the chemistry lab is calculated as: $393.75.

<h3>How to Calculate Total Cost?</h3>

In this scenario, we are given the following:

Total number of stations = 21 stations

Length of rubber tubing each of the stations in the chemistry lab needs = 5 feet

Total length of rubber tubing needed for all stations in the chemistry lab = 21 × 5 = 105 feet

Cost of 1 rubber tubing = $6.25 per yard

Convert 5 feet to yard:

1 yard = 3 feet

x yard = 5 feet

x = (5 × 1)/3

x = 5/3 feet.

So, the cost of 1 rubber tubing = $6.25 per 5/3

Cost of total length of tubbing needed = (105 × 6.25)/5/3 = (105 × 6.25) × 3/5

Cost of total length of tubbing needed = $393.75

Therefore, the cost to equip all the stations in the chemistry lab is calculated as: $393.75.

Learn more about the How to Calculate Total Cost on:

brainly.com/question/2021001

#SPJ1

6 0
2 years ago
X/6&gt;-8 . Can you exsplain to me how you do this answer for my math class
Oduvanchick [21]

Answer:

X>−48

Step-by-step explanation:

X/6>-8 multiply both sides by 6

X>−8×6  simplify 8*6 into 48

X>−48

5 0
2 years ago
Read 2 more answers
Solve the formula 27a+1/2b=4 for a.
MakcuM [25]

Answer:

a = 4/27 - b/54

Step-by-step explanation:

27a+1/2b=4

Subtract 1/2 b from each side

27a+1/2b - 1/2 b=4-1/2 b

27a = 4 - 1/2 b

Divide each side by 27

27a/27 = 4/27 - 1/2 b/27

a = 4/27 - b/54

7 0
3 years ago
Read 2 more answers
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