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Xelga [282]
3 years ago
10

Write the point-slope form of the given line that passes through the points (0, 3) and (4, 0). Identify (x1, y1) as the x-interc

ept of the line. Include your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution.
Mathematics
1 answer:
Sindrei [870]3 years ago
5 0
Now, bear in mind that, when the y-axis gets intercepted, x = 0, therefore 0,3 is really the y-intercept.

and when the x-axis gets intercepted, y = 0, therefore 4,0 is the x-intercept, thus we will use this one in the point-slope form then.

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 0}}\quad ,&{{ 3}})\quad 
%   (c,d)
&({{ 4}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-3}{4-0}\implies -\cfrac{3}{4}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-0=-\cfrac{3}{4}(x-4)
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Susan Marciano invested part of her $37,000 bonus in a fund that paid a 12% profit and invested the rest in stock that suffered
Bad White [126]

Answer:

The amount invested in funds that earned 12% profit is 31000

The amount invested in stock that suffered 5% loss is 6,000.

Step-by-step explanation:

Let x be the amount invested in funds that earned 12%.

Then the amount invested in stock that suffered 5% loss is 37000 - x.

The profit from investment in funds is = 12% of x

                                                               = 0.12·x

The loss from investment in stock is = 5% of (37000 - x)

                                                            = 0.05 × (37000 - x)

The net profit is 0.12·x - 0.05 × (37000 - x)

As the net profit given in the problem is $3420, we have :

0.12·x - 0.05 × (37000 - x) = 3420

Solving for x, we have :

12·x - 5 × (37000 - x) = 342000 (multiply both sides by 100)

12·x - 185000 + 5·x = 342000

17·x = 527000

⇒ x = 31000

Hence, The amount invested in funds that earned 12% profit is 31000 and the amount invested in stock that suffered 5% loss is 37000 - x = 37000 - 31000 = 6,000.

6 0
4 years ago
The local amusement park was interested in the average wait time at their most popular roller coaster at the peak park time (2 p
Effectus [21]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

118, 124, 108, 116, 99, 125, 138, 118, 119, 121, 65, 130, 120

Ordered data:

65, 99, 108, 116, 118, 118, 119, 120, 121, 124, 125, 130, 138

1.)

90th percentile :

0.9(n + 1)th term

n = sample size = 13

0.9(14) th term

= 12.6th term

= (12 + 13)th / 2

= (130 + 138) / 2

= 134

Third quartile (Q3) = 75th percentile

0.75(n + 1)th term

n = sample size = 13

0.75(14) th term

= 10.5th term

= (10 + 11)th / 2

= (124 + 125) / 2

= 124.5

What is the first quartile?

First quartile (Q1) :

0.25(n + 1)th term

n = sample size = 13

0.25(14) th term

= 3.5th term

= (3 + 4)th / 2

= (108 + 116) / 2

= 112

(4) What is the 10th percentile?

0.1(n + 1)th term

n = sample size = 13

0.1(14) th term

= 1.4th term

= (1 + 2)th / 2

= (65 + 99) / 2

= 82

(5) 65tb percentile :

0.65(n + 1)th term

n = sample size = 13

0.65(14) th term

= 9.1th term

= (9 + 10)th / 2

= (121 + 124) / 2)

= 122.5

(6) What is the IQR?

Q3 - Q1

124.5 - 112

= 12.5

(7) What are the lower and upper limits?

Maximum = 138

Minimum = 65

4 0
3 years ago
What is the x intercept Y=-6x+8
forsale [732]
\large\begin{array}{l} \textsf{You can easily find x intercept of a line by solving}\\\textsf{the equation below:}\\\\ \mathsf{y=0}\\\\ \mathsf{-6x+8=0}\\\\ \mathsf{-6x=-8}\\\\ \mathsf{x=\dfrac{-8}{-6}}\\\\ \boxed{\begin{array}{c}\mathsf{x=\dfrac{4}{3}} \end{array}} \end{array}

4 0
3 years ago
Read 2 more answers
The sodium content of a popular sports drink is listed as 200 mg in a 32-oz bottle. Analysis of 20 bottles indicates a sample me
julia-pushkina [17]

Answer:

The sample does not contradicts the manufacturer's claim.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 200 mg

Sample mean, \bar{x} = 211.5 mg

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s = 18.5 mg

a) First, we design the null and the alternate hypothesis  for a two tailed test

H_{0}: \mu = 200\\H_A: \mu \neq 200

We use Two-tailed t test to perform this hypothesis.

b) Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{211.5 - 200}{\frac{18.5}{\sqrt{20}} } = 2.7799

c) Now,

t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = \pm 2.0930

Since, the calculated t-statistic does not lie in the range of the acceptance region(-2.0930,2.0930), we reject the null hypothesis.

Thus, the sample does not contradicts the manufacturer's claim.

d) P-value = 0.011934

Since the p-value is less than the significance level, we reject the null hypothesis and accept the alternate hypothesis.

Yes, both approach the critical value and the p-value approach gave the same results.

4 0
3 years ago
Help ASAP!!<br><br> Worth 40 points!!!
Vlad1618 [11]
12 x g + 1
Hope this help you
7 0
3 years ago
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