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nikdorinn [45]
2 years ago
13

In one or two sentences briefly describe the functions of the structures of the immune system:

Mathematics
2 answers:
CaHeK987 [17]2 years ago
4 0
Answer is F because of bones
Margaret [11]2 years ago
4 0

Answer:

Lymphatic vessels, spleen, Thymus, Bone marrow. Therefore, JIFE is the answer.

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Anyone mind helping me out?
Airida [17]
<h2>6 is the answer.</h2>

just simple

3 0
3 years ago
What is the factored form of 8x2 + 12x? 4(4x2 + 8x) 4x(2x + 3) 8x(x + 4) 8x(x2 + 4)
earnstyle [38]
So I'm guessing that the x2 is your way of saying 2 is the exponent right? In that case the equation would be 8x^2 + 12x
Well you would have to pull out the gcf which in this case will be 4x after pulling out the gcf you should get 4x(2x + 3)
8 0
3 years ago
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Jasmine took a cab home from her office. The cab charged a flat fee of $4, plus $2 per mile. Jasmine paid $32 for the trip. How
vaieri [72.5K]
To solve, make an equation. The equation would be
$32 = 4 + 2x
x represents the miles driven
to solve, subtract 4 from each side of the equation.
$32-4 = 4-4 + 2x
The equation is now 
$28 = 2x
Now you divide by 2 on each side.
$28 ÷ 2 = 2x ÷ 2
simplify
14 = x
The answer is 14 miles
3 0
3 years ago
Whats the slope of (2,-5),(-6,5)​
Makovka662 [10]
The slope of the line with the points (2,-5) and (-6,5) is 5/-4 (or 10/-8).
3 0
3 years ago
Write an equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5.
TiliK225 [7]

we know that

For a polynomial, if x=a is a zero of the function, then (x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.

So

In this problem

If the cubic polynomial function has zeroes at 2, 3, and 5

then

the factors are

(x-2)\\ (x-3)\\ (x-5)

Part a) Can any of the roots have multiplicity?

The answer is No

If a cubic polynomial function has three different zeroes

then

the multiplicity of each factor is one

For instance, the cubic polynomial function has the zeroes

x=2\\ x=3\\ x=5

each occurring once.

Part b) How can you find a function that has these roots?

To find the cubic polynomial function multiply the factors and equate to zero

so

(x-2)*(x-3)*(x-5)=0\\ (x^{2} -3x-2x+6)*(x-5)=0\\ (x^{2} -5x+6)*(x-5)=0\\ x^{3} -5x^{2} -5x^{2} +25x+6x-30=0\\ x^{3}-10x^{2} +31x-30=0

therefore

the answer Part b) is

the cubic polynomial function is equal to

x^{3}-10x^{2} +31x-30=0

7 0
3 years ago
Read 2 more answers
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