Heres an easy question, What is 50223 - 53253 * 51 Good luck! ;)
2 answers:
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Answer:
BH= 108 --> 1st until 6th space
so, 108/6 = 18 for each space
DE...?
DE only use 1 space so the answers is 18 unit
I hope this helps^_^
Answer:
Height of shuttle at that instant = 1.17 miles
Step-by-step explanation:
Refer the given figure.
C is the position of rocket and B is the position of observer.
Here we need to find AC, that is the height of shuttle at that instant.
Using trigonometric rules on ΔABC, we have
Height of shuttle at that instant = AC = 1.17 miles
