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Molodets [167]
3 years ago
13

Find the area of the following triangle. Show yourwork!​

Mathematics
2 answers:
11111nata11111 [884]3 years ago
7 0

Answer:

man/woman show the triangle

antiseptic1488 [7]3 years ago
4 0

Answer: Illuminati confirmed

Step-by-step explanation: it’s an invisible triangle!

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Evaluate x+2.7 for x=-1.5
jonny [76]

Answer:

1.2

Step-by-step explanation:

First make -1.5 equal to 0.

We'll have to add 1.5, right?

So 1.5 is in 2.7.

So now its 0 + ? = ?

2.7 - 1.5 = 1.2

So 0 + 1.2 = 1.2

Hope this helped.

3 0
3 years ago
Why does -2^6 equal -64 but -2 x -2 x -2 x -2 x -2 x -2 equal 64?<br> (The x's are multiplication)
NikAS [45]

Answer:

when there are no parentheses around the base, this being -2 we put parentheses around the the 2 and the exponent so it will look like -(2^6) making whatever answer you get negative.

when you put parentheses around the base (-2)^6 you will get 64  

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Solve the system of linear equations. <br>- 3x + 5y = 13 <br> x + 4y = -10 ​
Molodets [167]

Answer:

(-6,-1)

Step-by-step explanation:

5 0
3 years ago
Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)
GarryVolchara [31]

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

8 0
1 year ago
A stamp club president equally distrubutes two different sets of stamps among club memebers. One set contains 18 stamps. The oth
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