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melomori [17]
3 years ago
8

Once a computer worm infects a personal computer via an infected e-mail message, it sends a copy of itself to 100 e-mail address

es it finds in the electronic message mailbox on this personal computer. What is the maximum number of different computers this one computer can infect in the time it takes for the infected message to be forwarded five times?
Mathematics
1 answer:
Nataly [62]3 years ago
4 0

Answer:

63

Step-by-step explanation:

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Find slope of the graph 9x-3y=15
LekaFEV [45]
<h3><u>Explanation</u></h3>
  • Convert the equation into slope-intercept form.

y = mx + b

where m = slope and b = y-intercept.

What we have to do is to make the y-term as the subject of equation.

9x - 3y = 15 \\ 9x - 15 = 3y \\  \frac{9x - 15}{3}  = y

  • Simplify

\frac{9x}{3}  -  \frac{15}{3}  = y \\ 3x - 5 = y  \\ y = 3x - 5

From y = mx+b, the slope is 3.

<h3><u>Answer</u></h3>

\large \boxed {slope = 3}

4 0
3 years ago
Write each Percent as a decimal and as a mixed number or fraction in simplest form
sveticcg [70]

p\%=\dfrac{p}{100}\\\\225\%=\dfrac{225}{100}=2\dfrac{25}{100}=2.25=2\dfrac{1}{4}\\\\550\%=\dfrac{550}{100}=\dfrac{55}{10}=5\dfrac{5}{10}=5.5=5\dfrac{1}{2}\\\\0.8\%=\dfrac{0.8}{100}=\dfrac{0.8\cdot10}{100\cdot10}=\dfrac{8}{1,000}=0.008=\dfrac{1}{125}\\\\0.06\%=\dfrac{0.06}{100}=\dfrac{0.06\cdot100}{100\cdot100}=\dfrac{6}{10,000}=0.0006=\dfrac{3}{5,000}

6 0
2 years ago
A 150 no container can hold 23.6 g of aluminum what is the density of the aluminum?
Drupady [299]

Answer:

# The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The volume of the container is 4/17 ≅ 0.235 cm³

# The mass of iron is 1225 g

Step-by-step explanation:

* Lets explain how to solve the problem

- Density is a measurement that compares the amount of matter

 of an object to its volume [ Density = mass/volume]

- Density is found by dividing the mass of an object by its volume

- The unit of measuring density is gram per centimeter³ (milliliter)

* Lets solve the problems

# A container of volume 150 cm³ can hold 23.6 g of aluminum

∵ Density = mass/volume

∵ The mass = 23.6 g

∵ The volume = 150 cm³

∴ The density = 23.6/150 = 59/375 ≅ 0.157 g/cm³

* The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The density of mercury is 13.6 g/cm³ at 23 C°

- A container can hold 3.2 g of mercury at this temperature

∵ Density = mass/volume

∵ The mass = 3.2 g

∵ The density = 13.6 g/cm³

∴ 13.6 = 3.2/volume

- By using cross multiplication

∴ The volume = 3.2/13.6 = 4/17 cm³

* The volume of the container is 4/17 ≅ 0.235 cm³

# The density of the iron is 4.9 g/cm³

- The beaker has a volume 250 ml

∵ Density = mass/volume

∵ The ml = cm³

∴ The volume of the beaker is 250 cm³

∵ The density = 4.9 g/cm³

∴ 4.9 = mass/250

- Multiply both sides by 250

∴ mass = 1225 g

* The mass of iron is 1225 g

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You organize a garage sale. You have $30 at the beginning of the sale. You earn an average of $20 per hour. Write an equation th
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30+(20x)=y

30 is the money you had from the start of the garage sale.

20 is what you are getting per hour

y equals the total money you are earning at the end of the garage sale

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3 years ago
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