The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
<h3>Calculating Maximum speed</h3>
From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus
From the give information,
The maximum walking speed, S, is given by
S = √gL
Where g = 32ft/sec
and L is the length of the animal's leg
Thus,
For a Giraffe with a leg length of 6 feet
S = √32×6
S = √192
S = 13.856 ft/sec
For a Hippopotamus with a leg length of 3 feet
S = √32×3
S = √96
S = 9.798 ft/sec
Now, we will determine how many times greater 13.856 is than 9.798
13.856/9.798 = 1.41
Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
Learn more on Calculating Speed here: brainly.com/question/15784810
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A) they fornite a right angle and 2 acute angles(not 100% sure of what the Questions is asking)
B) they appear to form a triangle
C) the angles add up to 180 as they always do in all triangles
B)
Answer:
1:2, 2:4, 3:6
Step-by-step explanation:
If you times 1:2 by 2, you get 2:4. If you times 1:2 by 3, you get 3:6.
You have to multiply each individual number in the ratio.
Responder:
42 bombones
Explicación paso a paso:
Dado que :
Número de bombones = 60
Cantidad consumida por Eba = 1/5 * 60 = 12
Cantidad comida por Ana = 1/2 * 60 = 30
Cantidad de chocolate que comieron Eba y Ana:
(12 + 30) = 42
De ahí que Ana y Eba se comieran 42 bombones
Answer:
Distance =(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√
Step-by-step explanation:
The answer is provided above.
Distance =(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√
Hope this helps.
