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3 years ago

Write assembly programs with the following I/O

Computers and Technology

1 answer:

Nat2105 [25]3 years ago

5 0

Answer:

Explanation:

copy to code:

#include <iostream>

#include <string>

using namespace std;

int main()

{

//total bill amount

float totalBill=0;

//no of customers

int noOfCustomer=0;

//no of drinks

int noOfDrinks;

//drink type

char drinkType;

//no of sandwiches

int noOfSandwiches;

int sandWitchSize;

cout<<"Enter the number of customers : ";

cin>>noOfCustomer;

//loop through no of customers

for(int i=1;i<=noOfCustomer;i++){

totalBill=0;

cout<<"Enter how many drinks ? ";

cin>>noOfDrinks;

cout<<"Enter what kind of drink (S=Soda ,W=Water) ";

cin>>drinkType;

if(drinkType=='w' || drinkType=='W'){

totalBill +=noOfDrinks*1;

}else if(drinkType=='s' || drinkType=='S'){

totalBill +=noOfDrinks*2;

}

cout<<"How many Sandwiches : ";

cin>>noOfSandwiches;

cout<<"What size of sandwich (10/12 inches) ? :";

cin>>sandWitchSize;

if(sandWitchSize==10){

totalBill+= noOfSandwiches*3;

}else if(sandWitchSize==12){

totalBill+= noOfSandwiches*5;

}

cout<<"Your total bill "<<totalBill<<endl;

}

return 0;

}

Enter the number of customers : 2

How many drinks? 2

What kind of drink(S=Soda and W=Water)? w

How many sandwiches? 3

What size of sanwich(10/12inches) ? 12

Your total bill = $ 17

How many drinks? 4

What kind of drink(S=Soda and W=Water)? s

How many sandwiches? 4

What size of sanwich(10/12inches) ? 10

Your total bill = $ 20

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4 years ago

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zepelin [54]

Answer:

// program in C++.

// headres

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// array

int temperatures[7];

// count variable

int count=0;

cout<<"Enter the temperature of all days:";

for(int a=0;a<7;a++)

{

// read temperature of 7 days

cin>>temperatures[a];

// find temperature is extreme or not

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// count

count++;

}

// print count of extreme temperature

cout<<"number of days of extreme temperature:"<<count<<endl;

return 0;

}

Explanation:

Create an array of size 7 to store the temperature of all days of week.Read the temperature of each day.If the temperature is less than -10 or greater than 25 then increment the count.This will count the number of days of extreme temperature.Print the count.

Output:

Enter the temperature of all days:-20 12 18 30 32 -15 15

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3 years ago

Write a program that allows the user to enter a start time and a future time. Include a function named compute Difference that t

Aleonysh [2.5K]

Step 1

Following is the c++ program:

Variables used:

startHours, startMins are used to store the starting time of time machine.

futureHours, futureMins are used to store the future time of time machine.

xAM variable is used to store meridiem of start and future time.

isSAM is boolean variable that is true if starting time is AM.

isFAM is boolean variable that is true if future time is AM.

Functions:

main() is used to call computeDifference() function that will calculate the difference between the start and future time.

computeDifference() takes as input six variables from the user and then apply the following logic to compute the difference between the start and future time:

If Meridien of both start and future time are the same, then simply subtract the start time from the future time.

Difference = future minutes – start minutes

If Meridien of both start and future time are different, then apply the following formula to calculate difference:

Difference = (12 * 60 – start minutes) + future minutes

Step 2

Program :

#include <iostream> //header file for input and output

using namespace std;

//calculate the time difference(in minutes) between start time and future time.

int computeDifference(int startHours, int startMins, bool isSAM, int futureHours, int futureMins, bool isFAM) {

int difference = 0; //to store difference

startMins = startHours * 60 + startMins; //converting in minutes.

futureMins = futureHours * 60 + futureMins; //converting in minutes.

//applying formula for difference.

if (isSAM == isFAM) {

difference = futureMins - startMins;

} else if (isSAM == true && isFAM == false) {

difference = (12 * 60 - startMins) + futureMins;

}

int main() {

int startHours, startMins; //it will store start time

int futureHours, futureMins; //it will store future time.

string xAM; //it will store meridiem.

bool isSAM; //it will be true if start time is AM.

bool isFAM; //it will be true if future time is in AM.

int difference = 0; //it will store difference.

cout << "Enter start time of time machine as 'HH MM AM/PM': "; //take input from

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4 years ago

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Answer:

a. x^<i>(j)

Explanation:

The solution has been explained in the question; however, I will provide further explanation.

The sequence to access a word is:

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In other words, you first access the training example, before you gain access to the word being searched for.

Rewrite the following:

Training example --> Word

as:

ith training example --> jth word

Hence, the representation is:

$x^{(i)$

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3 years ago