1) The measures of the opposite angles of an inscribed quadrilateral are supplementary, add up to 180.
That means that angle ROP and angle RQP are supplementary.
We can add them and set them equal to 180 so that we can solve for x first.
∠ROP + RQP = 180
x + 17 + 6x - 5 = 180
7x + 12 = 180
7x = 168
x = 24
Now use the 24 for x and solve for the measure of angle ROP.
∠ROP = x + 17
∠ROP = 24 + 17
∠ROP = 41
The answer is A
2) The answer is A.
Hope this helps :)
Answer:
I could really use some help on a question that I am struggling with. Can you help? Here it is...
Step-by-step explanation:
What is the interest on $3,500 borrowed for two years at 2.5% interest?
Unfortunately, there is no given table. However, assuming no air resistance, the projectile moves in constant acceleration in the y-axis, while constant velocity in the x-axis. If the total time of flight is 6 seconds, then at 3 seconds the reaches its maximum height. Also, there is no given initial velocity, which means any useful calculation is impossible.
Sorry I’m only answering this so I can ask
The length of q, to the nearest 10th of a centimeter is 7.6 cm.
Given in question,
In ΔOPQ,
o = 9.2 cm
p = 2.4 cm
∠Q = 37°
Cosine formula ⇒ cos θ = 
Putting the values in equation,
cos 37 = 
0.799 = 
0.799*44.16 = 90.4 - 
32.28 = 90.4 -
= 90.4 - 32.28
= 58.12
q = 7.6 cm (to nearest 10th)
Hence, length of q is 7.6 cm.
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