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faust18 [17]
2 years ago
8

Solve. 3/4 + 4/4 = ?/?

Mathematics
1 answer:
shepuryov [24]2 years ago
5 0
Since they have the same denominator (4) which is the number on the bottom of the fraction, you can just add the numerators (3 and 4), which are on the top of the fraction, together:

3/4 + 4/4 = 7/4
You might be interested in
Last PreCalc Question, Need help with writing piecewise functions with graphs. Giving brainliest!
LekaFEV [45]

The piece-wise linear functions can be written as follows:

  • f(x) = x, x \leq -2.
  • f(x) = -x - 7, -2 < x \leq 1.
  • f(x) = 2x - 9, x > 1.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

For x equal or less than -2, the line passes through (-3,-3) and (-2,-2), hence the rule is:

f(x) = x, x \leq -2.

For x greater than -2 up to 1, the y-intercept is of -7, and the line also passes through (1,-8), hence the rule is:

f(x) = -x - 7, -2 < x \leq 1.

For x greater than 1, the function goes through (2,-5) and (3,-3), hence the slope is:

m = (-3 - (-5))(3 - 2) = 2.

The rule is:

y = 2x + b.

When x = 2, y = -5, hence:

-5 = 2(2) + b

b = -9.

Hence:

f(x) = 2x - 9, x > 1.

More can be learned about linear functions at brainly.com/question/24808124

#SPJ1

5 0
2 years ago
9. Find (f.g)(a) if f(a) = . and g(a) = 2². Fully simplify your answer.
Aleks04 [339]

D is your answer ....

8 0
3 years ago
How to mulitiply 8.18 times 2.8 don’t understand
schepotkina [342]

Answer:

Multiply it like a normal number.

Step-by-step explanation:

Take the point away in both numbers

line the numbers up and add the zero at the end of 28

multiply

add the decimal point back after solved (3 decimal points)

 818

x280

-----------

4 0
3 years ago
Jordan will hike the trail at a rate of 4mph. Write a linear equation to represent the distance Jordan still has to walk after x
goldfiish [28.3K]

The linear equation would be y = 18 - 4x which represents the distance Jordan still has to walk after x hours.

The y-intercept represents the total distance Jordan has to walk.

<h3>What is the distance?</h3>

Distance is defined as the product of speed and time.

We have to determine the distance.

So distance = speed× time

Given that his speed is 4 mph and x hours of walking, then:

So distance = 4 × x

Let it Start of the trail: 0 miles

And the end of the trail: 18 miles​

The trail length is 18 miles, so if he walked 1 mile, 18 - 1 = 17 miles are left, in general:

⇒ y = 17 - 4(x)

Here y would be the distance Jordan still has to walk.

The y-intercept would be if substitute x = 0, then:

⇒ y = 17- 4(0)

⇒ y = 17

This represents the total distance Jordan has to walk

Hence, the linear equation would be y = 18 - 4x which represents the distance Jordan still has to walk after x hours.

The y-intercept represents the total distance Jordan has to walk.

Learn more about the distance here:

brainly.com/question/13269893

#SPJ1

8 0
10 months ago
<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B
inysia [295]

\large \bigstar \frak{ } \large\underline{\sf{Solution-}}

Consider, LHS

\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered}  \\  \\  \text{So, using this identity, we get} \\  \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered}  \\

So, using this identity, we get

\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

can be rewritten as

\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}

<h2>Hence,</h2>

\begin{gathered} \\ \rm\implies \:\boxed{\sf{  \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}

\rule{190pt}{2pt}

5 0
2 years ago
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