You have to be very careful how you interpret this question -- more specifically what you do about the acceleration. It's constant. That makes a usable even though the acceleration is not part of the equation.
You can't use b because it requires that you know the acceleration or distance to find the other. So don't choose b.
Again you need a value for the acceleration to find d. You have 2 unknowns and 1 equation. so C is out.
Same with D
A is your answer.
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Answer:
Step-by-step explanation:
2^4= 2*2*2*2= 16
2^4= 2*2*2*2= 16
5^2= 25
(16+16)*25
32*25=800
<span>
4. The x-coordinate of the solution is 9.</span><span>
5. The y-coordinate of the solution is −8 .</span><span>
6.The ordered pair that is the solution to the system lies in Quadrant IV .</span><span>
Proof:
Solve the following system:
{4 x + 3 y = 12 | (equation 1)
{2 x + 3 y = -6 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x + 3 y = 12 | (equation 1)
{0 x+(3 y)/2 = -12 | (equation 2)
Multiply equation 2 by 2/3:
{4 x + 3 y = 12 | (equation 1)
{0 x+y = -8 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 36 | (equation 1)
{0 x+y = -8 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 9 | (equation 1)
{0 x+y = -8 | (equation 2)
Collect results:
Answer: {x = 9 , y = -8</span>