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Iteru [2.4K]
2 years ago
14

Kylan had 1 ⅜ kilograms of fertilizer. He used some to fertilize a flower bed, and he only had ⅔ kilograms left. How much fertil

izer was used in the flower bed?
Mathematics
1 answer:
MrMuchimi2 years ago
6 0

Answer: 17/24

Step-by-step explanation:

let x be the fertilizer used in the flower bed

to find how much he has left

1 3/8 - x = 2/3

the fraction 1 3/8 we can write as 11/8

11/8 - x = 2/3

11/8 -2/3= x

we need the common denominator between 8 and 3, which is 24

33/24-16/24=17/24

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I don´t understand this: Lin’s father is paying for a $20 meal. a) He has a 15%-off coupon for the meal. How much is the discoun
Naddika [18.5K]

You'll have to set this up as two separate problems. First, we want to take 15% off the original $20 bill. To do this, you're going to multiply 20 by .15, which gives you $3. So, 15% off $20 is $17.

Now, we want to find 7% of the new bill, so we're going to multiply 17 by .07 to get $1.19, and add it to the $17, making the final bill $18.19. You could also multiply $17 by 1.07 to get your final total without the extra step in the middle, but only do that once you're comfortable with the math.

Pls give brainiest

7 0
3 years ago
What is the percent of change from 100 to 14
Alik [6]

Answer:

there is an 86% change

4 0
3 years ago
Find maclaurin series
Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}

The first 3 terms of the series are

\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}

7 0
2 years ago
Solve the linear equation. 3x = 24 x = ?
trapecia [35]

Answer:

3x =24

x = 24 -3

x = 21 (ans)

6 0
3 years ago
If you run for 0.4 hours at 7 mph, how fast should you walk during the next 0.8 hours to have the average speed of 5 mph?
Orlov [11]

4mph

0.4 x 7 mph =2.8 miles - distance run.

Let the required speed =S

[2.8 + 0.8S] / [0.4+0.8] =5, solve for S

S =4 mph - must walk to attain an average of 5 mph, or:

6 miles / 1.2 hours =5 mph

8 0
4 years ago
Read 2 more answers
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