8x+5=6x+1variables on both sides and I need help to the question

Mathematics

1 answer:

ddd [48]3 years ago

3 0

Answer: x = -2

Step-by-step explanation: When we have this kind of a setup, we want to put our variables together on one side of the equation and our numbers together on the other side of the equation.

So first, let's put our variables together on the left side

by subtracting 6x from both sides of the equation.

That gives us 2x + 5 = 1.

Now we can move our numbers to the right by subtracting

5 from both sides and we get 2x = -4.

Since x is being multiplied by 2, divide both sides

by 2 to get x by itself and we end up with x = -2.

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-5y=-5 7x+6y=7 is (5,1) a solution of the system? PLEASE HELP!!!!

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$( \frac{1}{7}, 1)$

explanation:

$- 5y = - 5 \\ 7x + 6y = 7 \\ divide \: both \: sides \: by \: - 5 \\ \\ y = 1 \\ \\ 7x + 6y = 7 \\ substitute \: the \: value \: of \: y \: into \: an \\ equation \\ \\ 7x + 6 \times 1 = 7 \\ multiply \: 6 \: to \: 1 \\ \\ 7x + 6 = 7 \\ subtract \: 6 \: from \: both \: sides \\ \\ 7x = 1 \\ divide \: both \: sides \: by \: 7 \\ \\ x = \frac{1}{7} \\ \\ (\frac{1}{7}, 1)$