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miss Akunina [59]
3 years ago
10

Please help !!!!!!!!!!!!

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0

Answer:

25+40

Step-by-step explanation:

for the area of a triangle you multiple the base times the height. for the area of the square it is the length times width.

NOTE: to completely answer just add 25+40

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An article in The Engineer (Redesign for Suspect Wiring," June 1990) reported the results of an investigation into wiring errors
GarryVolchara [31]

Answer:

a) The 99% confidence interval on the proportion of aircraft that have such wiring errors is (0.0005, 0.0095).

b) A sample of 408 is required.

c) A sample of 20465 is required.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Of 1600 randomly selected aircraft, eight were found to have wiring errors that could display incorrect information to the flight crew.

This means that n = 1600, \pi = \frac{8}{1600} = 0.005

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.005 - 2.575\sqrt{\frac{0.005*0.995}{1600}} = 0.0005

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.005 + 2.575\sqrt{\frac{0.005*0.995}{1600}} = 0.0095

The 99% confidence interval on the proportion of aircraft that have such wiring errors is (0.0005, 0.0095).

b. Suppose we use the information in this example to provide a preliminary estimate of p. How large a sample would be required to produce an estimate of p that we are 99% confident differs from the true value by at most 0.009?

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

A sample of n is required, and n is found for M = 0.009. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.009 = 2.575\sqrt{\frac{0.005*0.995}{n}}

0.009\sqrt{n} = 2.575\sqrt{0.005*0.995}

\sqrt{n} = \frac{2.575\sqrt{0.005*0.995}}{0.009}

(\sqrt{n})^2 = (\frac{2.575\sqrt{0.005*0.995}}{0.009})^2

n = 407.3

Rounding up:

A sample of 408 is required.

c. Suppose we did not have a preliminary estimate of p. How large a sample would be required if we wanted to be at least 99% confident that the sample proportion differs from the true proportion by at most 0.009 regardless of the true value of p?

Since we have no estimate, we use \pi = 0.5

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.009 = 2.575\sqrt{\frac{0.5*0.5}{n}}

0.009\sqrt{n} = 2.575*0.5

\sqrt{n} = \frac{2.575*0.5}{0.009}

(\sqrt{n})^2 = (\frac{2.575*0.5}{0.009})^2

n = 20464.9

Rounding up:

A sample of 20465 is required.

8 0
3 years ago
7. Mike earns $12.00 per hour at a restaurant. On Thursday he spent 1 1/4 hours on
Goryan [66]
$68.60 would be the correct answer
6 0
3 years ago
What is 7/8+14/16+4/5
Jlenok [28]

Answer:

The answer is 2.55

Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
A car is driving at 55 kilometers per hour . How far ,in meters ,does it travel in 5 seconds
Sedbober [7]

Answer:

76.3889 meters

Step-by-step explanation:

4 0
3 years ago
An X-ray machine for animals costs $125,000. If the loan is for 10 years, and the interest paid is $65,625, what is the interest
miskamm [114]

Answer:

52.5%

Step-by-step explanation:

the cost is $125,000

if loaned for 10 years the interest paid on the official amount is$65,625

to find interest rate you:

this is the formula

interest/cost price multiplied by 100%

P.S it's 100% because the unit for interest rate is %

Therefore:

$65,625/$125,000 x 100%

the zero's on 100 cancel the ones on the $125,000.

it becomes $1250

now it's $65,652/$1250

which equals to

52.5%

hope it helps

mark me brainly

4 0
3 years ago
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