Which of the following choices is equivalent to 1 + 8(2x + 3)?

Please someone answer these 2 questions

saveliy_v [14]

1. C
2.A
Hope this helps, good luck :D

4 0

2 years ago

The function f(x) varies inversely with x and f(x)=8 when x=3

Sedaia [141]

Answer:

$12$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form $y*x=k$ or $y=k/x$

In this problem we have

For $x=3$ -----> $f(x)=8$

so

Find the value of k

$f(x)*x=k$

substitute the value of x and f(x)

$8*3=k$

$k=24$

therefore

the equation is equal to

$f(x)=24/x$

For $x=2$ -------> substitute in the equation and find the value of f(x)

$f(x)=24/2=12$

6 0

2 years ago

Read 2 more answers

Find S18 for geometric series given a5=-6 and a2= -48

Ganezh [65]

an = a1r^(n-1)

a5 = a1 r^(5-1)

-6 =a1 r^4

a2 = a1 r^(2-1)

-48 = a1 r

divide

-6 =a1 r^4

---------------- yields 1/8 = r^3 take the cube root or each side

-48 = a1 r 1/2 = r

an = a1r^(n-1)

an = a1 (1/2)^ (n-1)

-48 = a1 (1/2) ^1

divide by 1/2

-96 = a1

an = -96 (1/2)^ (n-1)

the sum

Sn = a1[(r^n - 1/(r - 1)]

S18 = -96 [( (1/2) ^17 -1/ (1/2 -1)]

=-96 [ (1/2) ^ 17 -1 /-1/2]

= 192 * [-131071/131072]

approximately -192

3 0

3 years ago

If 18 is added to a certain number and the sum is divided by 6, the result is 1 more than 14 of the original number. Find the or

Katyanochek1 [597]

The original number is 72

(18+x)/6 = 1+14
1/6x + 3 = 1 + 14 (Distribute)
1/6x + 3 = (1+14) (Combine Like Terms)
1/6x + 3 = 15
- 3 = -3 (Subtract 3 From Both Sides)
1/6x = 12
(1/6x)*6 = 12 * 6 (Multiply Both Sides By 6)
x = 72

5 0

3 years ago

A Packaging Company produces boxes out of cardboard and has a specified weight of 16 oz. A random sample of 36 boxes yielded a s

user100 [1]

Answer:

The margin of error is of 0.73 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.005 = 0.995$ , so Z = 2.575.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.575\frac{1.7}{\sqrt{36}} = 0.73$

The margin of error is of 0.73 oz.

The lower end of the interval is the sample mean subtracted by M. So it is 15.3 - 0.73 = 14.57 oz.

The upper end of the interval is the sample mean added to M. So it is 15.3 + 0.73 = 16.03 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

4 0

2 years ago