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Natasha2012 [34]
3 years ago
13

Helpppppppppppppppppppppppppppppppppppp

Mathematics
1 answer:
yanalaym [24]3 years ago
6 0

Answer:

b

Step-by-step explanation:

a^3b^2c = b(a^3bc)

5bc = b(5c)

15a^2b = b(15a^2)

GCF = b

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1-tan^2(x)/sec^2 = cos(2x)
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By applying the formula of trigonometric function the right hand side will

be equal to right hand side which is 1-tan^{2} x/sec^{2}x=cos2x.

Given: 1-tan^{2} x/sec^{2}x=cos2x.

Taking right hand side first which is cos2x.

We know that cos2x=1-tan^{2}x/1+tan^{2}x

Now we will solve the left hand side of the equation give which is

1-tan^{2} x/sec^{2}x

=1-tan^{2}x/1+tan^{2}x

[secant square x minus tangent square x is equal to 1]

By putting both values left hand side and right hand side we will find our solution which is :

1-tan^{2}x/1+tan^{2}x=1-tan^{2}x/1+tan^{2}x.

Hence proved

Learn more about trigonometric functions at brainly.com/question/24349828

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1 year ago
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Step-by-step explanation:

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