Sqrtx^2+6x+9 if x≥3
please help quick idk how to do this at all
1 answer:
Answer:
x+3
Step-by-step explanation:
sqrt(x^2+6x+9)
factor
We know this is a perfect square trinomial
sqrt(( x+3)^2)
Taking the square root of a square
x+3
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Answer:
y = -6x — 13
Step-by-step explanation:
use y = mx + b equation and plug in what you know.
5 = -6(-3) + b —> solve for b
b = -13 —> plug in what you know into y=mx+b
ANSWER: y = -6x — 13
Answer:
Hope this helps
Step-by-step explanation:
Answer:3,-3
Step-by-step explanation:
difference of 2 squares
(x+3)(x-3)
x+3=0
x-3=0
x=3,-3
