uh idk um...
Okay well to answer this you have to work the problem out and enable to do that you have to look at the information provided, also STOP CHEATING AND FIGURE IT OUT
um i mean.....GOODLUCK!!!! I know you can do it :)
Uhhh I think it'd be C and... probably A or D. I'm not 100% sure, but if I was taking the test, that is what I would choose.
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I brlive that is the answer
This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181