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makkiz [27]
3 years ago
14

Determine the number of real solutions each quadratic equation has

Mathematics
1 answer:
Serjik [45]3 years ago
8 0

Answer:

where is your quadratic equation

Step-by-step explanation:

b^2-4ac>0=2 real # solutions

b^2-4ac=0=1 real # solutions

b^2-4ac<0=0 real # solutions

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1. How many degrees is x<br> .x<br> 41<br> 82<br> 20.5<br> o<br> 41<br> О<br> 10
Alja [10]

Answer:

Option (1)

Step-by-step explanation:

By the inscribed angle theorem inside a circle,

"Measure of an inscribed angle is half the measure of the intercepted arc"

\frac{1}{2}[m(arc AB)] = m(∠ABC)

m(arc AB) = 2[m(∠ABC)]

x = 2(41°)

x = 82°

Option (1) is the correct option.

5 0
3 years ago
Line segment ST is dilated to create line segment S'T' using the dilation rule DQ,2. 25. Point Q is the center of dilation. Line
abruzzese [7]

The distance between points S' and S is x= 2.5 units.

<h2>Given that</h2>

Line segment ST is dilated to create line segment S'T' using the dilation rule DQ 2. 25.

Point Q is the center of dilation.

Line segment ST is dilated to create line segment S prime T prime.

The length of QT is 1. 2 and the length of QS is 2.

The length of SS prime is x and the length of TT prime is 1. 5.

<h3>We have to determine</h3>

What is x, the distance between points S' and S?

<h3>According to the question</h3>

Line segment ST is dilated to create line segment S'T' using the dilation rule DQ, 2.25.

Also, SQ = 2 units, TQ = 1.2 units, TT'=1.5, SS' = x.

Since the line ST is dilated to S'T' with the center of dilation Q, the triangles STQ and S'T'Q must be similar.

We know that the corresponding sides of two similar triangles are proportional.

So, from ΔSTQ and ΔS'T'Q.

\dfrac{SQ}{S'Q} = \dfrac{TQ}{T'Q}\\&#10;\\&#10;\dfrac{SQ}{SQ+SS} = \dfrac{TQ}{TQ+TT'}\\&#10;\\ &#10;\dfrac{2}{2+x} = \dfrac{1.2}{1.2+1.5}\\\rm &#10;\\&#10;\dfrac{2}{2+x} = \dfrac{1.2}{2.7}\\\\ \dfrac{2}{2+x} = \dfrac{12}{27}\\\\2(27) = (2+x) 12\\\\ 54 = 24 + 12x\\&#10;\\&#10;12x = 54-24\\&#10;\\&#10;12x=30\\&#10;\\&#10;x = \dfrac{30}{12}\\&#10;\\&#10;x = 2.5

Hence, the distance between points S' and S is x= 2.5 units.

To know more about Pythagoras Theorem click the link given below.

brainly.com/question/16016926

5 0
3 years ago
A cuboid with a volume of 924cm^3 has dimensions 4cm, (x+1)cm and (x+11). Show clearly that x^2+12x-220=0 solve the equation by
garik1379 [7]

Answer:

x^2+12x-220=0 -- Proved

x = 10\ \ \ x = -22

Step-by-step explanation:

Given

Volume = 924cm^3

Dimension: 4cm; (x+1)cm; (x+11)cm

Required

Show that x^2+12x-220=0

The volume is calculated as:

4 * (x + 1) * (x + 11) = 924

Open the brackets

(4x + 4) * (x + 11) = 924

4x^2 + 44x + 4x + 44 = 924

4x^2 + 48x+ 44 = 924

Collect Like Terms

4x^2 + 48x+ 44 - 924=0

4x^2 + 48x -880=0

Divide through by 4

\frac{4x^2}{4} + \frac{48x}{4} -\frac{880}{4}=0

x^2+12x-220=0

Solving further:

Expand the expression

x^2 + 22x - 10x - 220 = 0

Factorize:

x(x + 22) - 10(x + 22) = 0

(x - 10)(x + 22) = 0

Split:

x - 10 = 0;\ \ \ x + 22 = 0

x = 10\ \ \ x = -22

5 0
3 years ago
Y'all, please help a girl out. ಥ_ಥ This problem is driving me nuts, but it's simple but I can't get the answer and that's why I'
elixir [45]

Answer:

The perimeter is 22.

Step-by-step explanation:

If you turn this shape into a rectangle, the perimeter doesn't change.

The width is given, it is 7.5. The height is BC+DE = 3.5

Then the perimeter is twice the width plus twice the height:

7.5*2 + 3.5*2 = 15+7 = 22

8 0
3 years ago
Lucia is wrapping packages that are in the shape of a triangular prism. The net of the prism is shown below: ( Help me answer th
solniwko [45]

Answer:

The total surface area of all 6 prisms is 6336 in^2.

Step-by-step explanation:

Let's find the surface area of ONE prism and then multiply that result by 6 to obtain the final answer.

One prism:

The area of the two 13 in by 26 in rectangular tabs is 2(13 in)(26 in), or 676 in^2 (subtotal);

The area of the two triangles of base 10 in and height 12 in is 2([1/2][10 in][12 in], or 120 in^2; and, finally,

The area of the 10 in by 26 in base is 260 in^2.

The total surface area of ONE prism is thus:

676 in^2 + 120 in^2 + 260 in^2, or 1056 in^2.

Now, because there are 6 of these prisms, multiply this last result by 6:

6(1056 in^2) = 6336 in^2.

The total surface area of all 6 prisms is 6336 in^2.

7 0
3 years ago
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