Solve for x over the real numbers:
3 x^2 + 5 x + 1 = 0
Hint: | Using the quadratic formula, solve for x.
x = (-5 ± sqrt(5^2 - 4×3))/(2×3) = (-5 ± sqrt(25 - 12))/6 = (-5 ± sqrt(13))/6:
Answer: x = (-5 + sqrt(13))/6 or x = (-5 - sqrt(13))/6
Answer: For a test? Nah, thats cheating
Step-by-step explanation: Just kidding, the answer is B...
I don't really understand what it's asking
,but I think it wants me to see if it's correct or not
I think this is fully incorrect because there has to be one girl out of those 50 people and I also think that there are gonna be 5th and 6th graders in those 50 people too!
The point ends up being ( 1, -1) and if you're graphing it you would put a dot on 1 and -1 on your graph and put a line connecting them (hope this helps)
Answer:
5) x = 1, y = -3
6) x = -20, y = 2
7) infinite solutions
8) no solutions
Step-by-step explanation:
5)
y = 5x - 8
y = -6x + 3
5x - 8 = -6x + 3
11x = 11
x = 1
y = 5 - 8
y = -3
6)
2x + 10y = -20
-x + 4y = 28
2x = -20 - 10y
x = - 10 - 5y
-x = 28 - 4y
x = -28 + 4y
-10 - 5y = -28 + 4y
-10 + 28 = 4y + 5y
18 = 9y
2 = y
2x + 20 = -20
2x = -40
x = -20
7)
this has infinite solutions because one equation is a simplified version of the other
8)
this has no solutions because 5 does not equal -5
9)
I can't graph on brainly, hope this helped though
