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Leokris [45]
3 years ago
12

HELP PLEASE

Advanced Placement (AP)
1 answer:
-BARSIC- [3]3 years ago
8 0

Answer: a

Explanation: competition is a bad thing. Since their  is no competition is benefiting not failing.

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Its funny how we use this for time4learning answer if you do it too
Elina [12.6K]

Answer: yes

Explanation: lol

3 0
3 years ago
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Which of these situations is most analogous to parallel computing?
seraphim [82]

Answer:

A.

Explanation:

The key word is simultaneously when it comes to parallel computing. Although the option <em>could </em>potentially be C, it's more likely to be A because it's "more right" in the words of my old English teacher. This is because A implies them working on it at the same time to reach the goal more effectively (another key word).

8 0
3 years ago
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EXTRA POINTS!!!
ad-work [718]

The concept of continuity relates to historical developments and processes because historians can link the happenings in the past to recent occurrences.

  • The concept of continuity simply explains the continuation of a cycle and it shows the connection that exists between historical events.

  • Changes take place at different times which are then linked forward and backward in time. Continuity refers to the continuance of themes.

  • The concept of continuity is vital as historians are able to link what has occurred earlier to the recent things that are happening. For example, Islam had an influence on African culture and its development.

In conclusion, continuity is important to historians.

Read related link on:

brainly.com/question/15498027

6 0
2 years ago
AP Calculus AB - Differentiating using the Product Rule
faltersainse [42]

Answer:

  h'(t) = (√t)(1 -5t²)/(2t)

Explanation:

First of all, your product rule needs to be written correctly.

  (f(x)g(x))' = f'(x)g(x) +f(x)g'(x)

You have ...

h(t)=\sqrt{t}(1-t^2)\\\\f(t)=\sqrt{t} \qquad f'(t)=\dfrac{1}{2\sqrt{t}}=\dfrac{\sqrt{t}}{2t}\\\\g(t)=1-t^2 \qquad g'(t)=-2t\\\\h'(t)=f'(t)g(t)+f(t)g'(t)=\dfrac{\sqrt{t}}{2t}(1-t^2)+\sqrt{t}(-2t)\\\\h'(t)=\dfrac{\sqrt{t}(1-t^2-4t^2)}{2t}=\dfrac{\sqrt{t}(1-5t^2)}{2t}

4 0
3 years ago
Can someone help me solve this I forgot how to solve this
lidiya [134]

Answer:

75

Explanation:

6 0
1 year ago
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